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3 years ago

How to write a equation that passes through the points (-1,12) and (4,-8)

Mathematics

1 answer:

defon3 years ago

8 0

Answer:

y - 12 = (-4/5)(x + 1)

Step-by-step explanation:

Let's use the point-slope formula y - k = m(x - h), where (h, k) is a point on the line and m is the slope of the line.

1. Find the slope. As we go from (-1, 12) to (4, 8), x (the run) increases by 5 and y (the rise) decreases by 4. Thus, the slope is m = rise/run = -4/5.

2. Plug into the formula (given above) the following:

-4/5 for m, -1 for x and 12 for y:

y - 12 = (-4/5)(x + 1)

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Kaitlyn saves $6 each week. After correctly carrying out the Solve step of the five-step problem-solving plan, which solution sh

ch4aika [34]

Answer:

1. 10 weeks

Step-by-step explanation:

Apparently, we want to find the number of weeks (w) that Kaitlyn must save $6 in order to have a total of $60.

... $6 × w = $60

Divide by $6 to get ...

... w = $60/$6 = 10

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Comment on the problem statement

The problem reads like we came in somewhere in the middle of it. We don't know what other steps you've been asked to perform, or any of the details of the problem you're asked to solve. We don't have Kaitllyn's initial balance, for example, which is essential to determining how long she must save. (If Kaitlyn's initial balance is $33, for example, she must only save for 4.5 weeks.)

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3 years ago

Rhombus ABCD has a diagonal BD¯¯¯¯¯.

ELEN [110]

Answer:

Solution given:

m∠ADB=(4x−12)°

m∠CDB=(3x+6)°

m∠ADC =?

Since diagonal BD bisect the angle <ADC

m∠ADB= m∠ADC

(4x-12)°=(3x+6)°

4x-3x=6-12

x=12+6

x=18°

again.

<ADB=m∠ADB+ m∠ADC=4×18-12+3×18+6=120°

the m∠ADC =120°

5 0

3 years ago

I REALLY NEED HELP

garri49 [273]

Look at the picture.

1.
$y=mx+b\\\\m=\dfrac{9}{3}=3\\\\b=4\\\\\boxed{f(x)=3x+4}$

2.
$f(x)=-2x+3\\\\for\ x=-2\to f(-2)=-2\cdot(-2)+3=4+3=7\to(-2;\ 7)\\for\ x=-1\to f(-1)=-2\cdot(-1)+3=2+3=5\to(-1;\ 5)\\for\ x=0\to f(0)=-2\cdot0+3=3\to(0;\ 3)\\for\ x=1\to f(1)=-2\cdot1+3=-2+3=1\to(1;\ 1)$

3.
$y=mx+b\\\\m=\dfrac{3}{6}=\dfrac{1}{2}=0.5\\\\b=-3\\\\\boxed{f(x)=0.5x-3}$
$for\ x=-6\to f(-6)=-6\\for\ x=-2\to f(-2)=-4\\for\ x=0\to f(0)=-3\\for\ x=6\to f(6)=0$

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3 years ago

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PSYCHO15rus [73]

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3 years ago

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Zigmanuir [339]

Answer:

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