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inysia [295]
3 years ago
6

3000 exercise books are arranged into 3 piles. The first pile has 10 more books than the second pile. The number of books in the

second pike is twice the number of books in the third pile. How many books are there in the third pile.
Mathematics
1 answer:
pochemuha3 years ago
7 0

Answer:

598 books

Step-by-step explanation:

Let x be the number of books in the 3rd pile. We will have then:

1st pile: 2x + 10

2nd pile: 2x

3rd pile: x

3000 = (2x + 10) + (2x) + (x)

3000 = 5x + 10

3000 - 10 = 5x

2990 = 5x

2990/5 = x

x = 598 books in the third pile!

We can check that:

3000 = 2*598 + 10 + 2*598 + 598

3000 = 1196 + 10 + 1196 + 598

3000 = 3000 CHECK!

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Answer:

f'(1x) = 2x

or

f'(0) = 4

Step-by-step explanation:

Hope this helps if not im sorry

5 0
3 years ago
The CEO of NJAD, a Real Estate Investment Fund, decided to design a new development inPolycity, New Jersey. She wants to build 3
shutvik [7]

The perimeter (P) is the sum of all sides:

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5 0
1 year ago
What is 1 1/2 + 2 1/3?i
natka813 [3]

Answer:

3.83 repeating 3

Step-by-step explanation:

6 0
3 years ago
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Justin wants to buy a new bike that costs $115. He has $40 and plans to
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Answer:

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Step-by-step explanation:

7 0
3 years ago
An ordinary (fair) die is a cube with the numbers through on the sides (represented by painted spots). Imagine that such a die i
mixer [17]

Complete question :

Compute the probability of each of the following events.

Event : The sum is greater than 6

Event : The sum is not divisible by 2

Answer:

7/12 ; 1/2

Step-by-step explanation:

Sample space :

2, 3, 4, 5, 6, 7

3, 4, 5, 6, 7, 8

4, 5, 6, 7, 8, 9

5, 6, 7, 8, 9, 10

6, 7, 8, 9, 10, 11

7, 8, 9, 10, 11, 12

Probability that sum is greater than 6:

Number of outcomes greater Than 6 = required outcomes = (7,7,7,7,7,7,8,8,8,8,8,9,9,9,9,10,10,10,11,11,12) = 21

Total sample space = total possible outcomes = 36

Probability = required outcome / Total possible outcomes

P(sum is greater Than 6) = 21 / 36

2.)

Obtaining an even number :

Sum not divisible by 2 = required outcomes = (3, 5, 7, 3, 5, 7, 5, 7, 9, 5, 7, 9, 7, 9, 11, 7, 9, 11) = 18

Total sample space = total possible outcomes = 36

P(sum is not divisible by 2) = 18 / 36 = 1 / 2

7 0
3 years ago
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