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Shalnov [3]
3 years ago
9

Solve for g : 3+2g=5g-9

Mathematics
1 answer:
KiRa [710]3 years ago
5 0
3+2g=5g-9
5g-2g=3+9
3g=12
3g/3=12/3
g=4
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dezoksy [38]
1a. (15x9)+(9x24)
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3 0
3 years ago
Find the exact value of cos(sin^-1(-5/13))
son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0
3 years ago
It costs $x for a round-trip bus ticket to the mall. You have $24. Select an inequality that represents how much money you can s
lorasvet [3.4K]

Answer:you have to make the inequality first

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A circle passes through the vertices of a square of side 20cm.Find the radius of the circle.
algol13

Answer:

14,1 cm

Step-by-step explanation:

If a circle passes through the vertices of a square then the diagonal of a square is a circle diameter.

We use Pytagoras Theorem to find out the length (L)  of the diagonal given that:

L²  =  (20)²  +  (20)²

L²  = 2* (20)²

L  = √2 * 20

L  = 1,4142* 20

L = 28,28 cm

L diagonal in the square is a diameter of the circle then radius of a circle is:

r = L/2   ⇒   r  = 28,28 /2   ⇒   r = 14,14 cm

3 0
2 years ago
Read 2 more answers
Mr.Ward runs a lot. He ran 45 minutes each day, 5 days each week , for 16 weeks . In that time, he ran 450 miles. What was his a
Savatey [412]

Answer:

7.5 miles per hour.

Step-by-step explanation:

We have been given that Mr. Ward runs a lot. He ran 45 minutes each day, 5 days each week, for 16 weeks.

First of all, we will find time for that Mr. Ward ran in 16 weeks.

We will multiply 5 by 16 to find number of days for that Mr. Ward ran and then we will multiply the result by 45 minutes to find the time.

\text{Time for that Mr. Ward ran in 16 weeks}=16\times 5\times 45\text{ minutes}

\text{Time for that Mr. Ward ran in 16 weeks}=3600\text{ minutes}

Now, we will divide 3600 minutes by 60 minutes to convert time into hours as:

\text{Hours}=\frac{3600}{60}=60

Now, we will divide 450 miles by 60 hours to find Mr. Ward's average speed as:

\text{Mr. Ward's average speed}=\frac{450\text{ miles}}{\text{60 hours}}

\text{Mr. Ward's average speed}=\frac{7.5\text{ miles}}{\text{ Hour}}

Therefore, Mr. Ward's average speed in 7.5 miles per hour.

7 0
3 years ago
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