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3 years ago

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Mathematics

1 answer:

ser-zykov [4K]3 years ago

5 0

Answer: D. Subtracting 9 from each side

Step-by-step explanation:

Always start with numbers without variables first before doing anything with x. And make sure one side must not equal 0 unless you're doing polynomials.

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Use the diagram of the right triangle above and round your answer to the nearest hundredth.

Svetlanka [38]

Option a: $17.32 \ {m}$ is the length of b

Explanation:

The angle of B is $\angle B=60^{\circ}$ and $a=10 \ m$

We need to determine the length of b.

First, let us determine the angle of A.

Since, ABC is a triangle, then all the angles add up to 180°

Thus, we have,

$\angle A+\angle B+\angle C=180^{\circ}$

$\angle A+60^{\circ}+90^{\circ}=180^{\circ}$

$\angle A+150^{\circ}=180^{\circ}$

$\angle A=30^{\circ}$

Thus, the angle of A is $\angle A=30^{\circ}$

Now, we shall determine the length of b using the sine law formula.

The formula for sine law is given by,

$\frac{a}{\sin A}=\frac{b}{\sin B}$

where $a=10 \ m$ , $\angle A=30^{\circ}$ , $\angle B=60^{\circ}$

Thus, we have,

$\frac{10}{\sin 30}=\frac{b}{\sin 60}$

Simplifying, we get,

$\frac{10}{0.5}=\frac{b}{0.866}$

Multiplying both sides by 0.866, we get,

$\frac{10\times0.866}{0.5}=b$

Multiplying the numerator, we have,

$\frac{8.66}{0.5}=b$

Dividing, we get,

$17.32=b$

Thus, the length of b is $b=17.32 \ m$

Hence, Option a is the correct answer.

7 0

2 years ago

Solve the given inequality and graph the solution on a number line. -x/3 + 5/2 < 2/2.

AleksAgata [21]

This is the working. the answer is x is less than half. the number line is beside it.

I hope it helped

8 0

3 years ago

A bottle filled with juice weighs 8 pounds. One morning, George drank 2/3 of the juice in the filled bottle. The bottle and the

Marysya12 [62]

The remaining weight of the empty bottle is 0.5 because each third of the bottle weighs 2.5 pounds and of the remaining juice and the bottle was 3 pounds 2.5 subtracted from 3 is 0.5

8 0

3 years ago

A chemical flows into a storage tank at a rate of (180+3t) liters per minute, where t is the time in minutes and 0<=t<=60

Yuliya22 [10]

Answer:

The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

Step-by-step explanation:

Consider the provided information.

A chemical flows into a storage tank at a rate of (180+3t) liters per minute,

Let $c(t)$ is the amount of chemical in the take at <em>t </em>time.

Now find the rate of change of chemical flow during the first 20 minutes.

$\int\limits^{20}_{0} {c'(t)} \, dt =\int\limits^{20}_0 {(180+3t)} \, dt$

$\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0$

$\int\limits^{20}_{0} {c'(t)} \, dt =3600+600$

$\int\limits^{20}_{0} {c'(t)} \, dt =4200$

So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

5 0

2 years ago

Two mechanics worked on a car. the first mechanic worked for 10 hours, and the second mechanic worked for 15 hours. together the

Yuliya22 [10]

Let x and y be the rate per hour for Mechanic 1 and 2 respectively.

Then,
x+y=205 ---------- (1)
Additionally,
10x+15y = 2500 ------ (2)

Solving equations 1 and 2;
Multiply (1) by 10 and subtract two from the result,
10x+10y = 2050
10x +15 y =2500
----------------------
-5 y = --450 => y = 450/5 = $90
Then,
x= 205-90 = $115

Therefore,
Mechanic 1 charged $115 per hour
Mechanic 2 charged $90 per hour

3 0

2 years ago