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Keith_Richards [23]
3 years ago
13

The combined area of two squares is 45 cm². Each side of one square is twice as long as a side of the other square. What is the

length of each side of the larger square?
Mathematics
1 answer:
12345 [234]3 years ago
5 0

Answer:

6 cm

Step-by-step explanation:

Let the smaller square have side of x then the larger square has side 2x

Sum the areas of the 2 squares and equate to 45

x² + (2x)² = 45

x² + 4x² = 45

5x² = 45 ( divide both sides by 5 )

x² = 9 ( take the square root of both sides )

x = \sqrt{9} = 3

side of smaller square = 3 cm

side of larger square = 2 × 3 = 6 cm

check : 3² + 6² = 9 + 36 = 45 cm² ← correct

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svetoff [14.1K]

Answer:  The cost of one rose bush is $7 and the cost of one shrub is also $7

Step-by-step explanation:

The situtation can be represented by the systems of the equations.

10x + 4y  =  98   x in this case is the cost of  one rose bushes

9x + 9y =  126     y  is the cost of one shrub.  

Solve the system of equation using the elimination method.

10x +4y = 98

9x + 9y = 126     eliminate the y variable so you will have to multiply 9 on top                                          and -4 down.

9(10x +4) = (98)(9)

-4(9x + 9y) = 126(-4)

You will now have the new two systems of equations

90x +36y = 882

-36x +-36y = -504    Now add the equations

0  + 54x = 378      

        54x = 378

  x= 7

Now we know that the cost of one rose bush is 7 so we will plot it into one of the equations and solve for the cost of one shrub.

90(7) +36y=882

630 +36y = 882

-630            -630

    36y = 252

   y = 7

Check:  10(7) + 4(7)= 98

              70  + 28 = 98

             98= 98  

so one rose bush is actually 7 dollars the same as 1 shrub.

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