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3 years ago

An architect makes a model of a new house. The model shows a tile patio in the backyard. In the model, each tile has length

Mathematics

1 answer:

zvonat [6]3 years ago

3 0

The two ways to find the ratio of the length is to turn the inches into feet or the feet into inches

So the answer can be solved like this:

1/36ft to 1/4ft which is 9:1 (blueprint size to actual size)

1/3in to 3in which is also 9:1 (blueprint size to actual size)

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Brady has $180 and makes $6 an hour. Nick has no money but makes $8 an hour.

a_sh-v [17]

Answer:

brady: y= 6h + 180

nick: y= 8h

Step-by-step explanation:

h in this situation is the same as x but I made it h to stand for hours worked

I'm also not sure if thats what you needed if not lmk

3 0

2 years ago

Read 2 more answers

Evaluate v(x) = 14-3x when x=-3, 0 and 4.

PtichkaEL [24]

Answer:

$v(-3)=23\\v(0)=14\\v(4)=2$

Step-by-step explanation:

$v(x)=14-3x$

$v(-3)=14-3(-3)\\\\v(-3)=14-(-9)\\\\v(-3)=23$

$v(0)=14-3(0)\\\\v(0)=14-0\\\\v(0)=14$

$v(4)=14-3(4)\\\\v(4)=14-12\\\\v(4)=2$

5 0

2 years ago

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The perimeter of a square is 32 centimeters. What is the length of one side?

Lubov Fominskaja [6]

L= length of one side of the square
Ok so we know the perimeter is 32 cm. Perimeter is the sum of all the sides of a shape. Now all four sides of a square are the same length. That means 4*L=32.
Now that we have the equation 4*L=32, we need to find a number that when multiplied by four, equals 32. Since 4*8=32, we know the answer must be 8cm.

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3 years ago

A fence is 692 m long. It is cut into three parts. Two parts are the same length, and the third part is 26 m longer than either

xenn [34]

One is 222
Two is 222
Three is 248

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3 years ago

This is a Differential Equations problem, I only need help on part 1 from question five. I need steps as well, thank you.

jolli1 [7]

Answer:

a) $y(t) = \sqrt{2t + 1 }$

b) 1.5 hours after thickness will be 2 inches.

Step-by-step explanation:

$\frac{dy}{dt} = \frac{1}{y} \\ \\ ydy = dt \\ \\ integrating \: both \: sides \\ \\ \int y \: dy = \int 1 \: dt \\ \\ \frac{ {y}^{2} }{2} = t + c \\ \\ {y}^{2} = 2t + 2c \\ \\ y (t)= \sqrt{2t + 2c} ...(1) \\ \\ a) \: \: \: plug \: t = 0 \: in \: (1) \\ \\ y (0)= \sqrt{2(0) +2 c} \\ \\ y (0)= \sqrt{0 +2 c} \\ \\ 1 = \sqrt{2c} \: \: ( \because \: y (0)=1) \\ \\ 2c = 1 \: \implies \: c = \frac{1}{2} \\ \\ plug \: c = \frac{1}{2} \: in \: (1) \\ \\ y(t) = \sqrt{2t + 2 \times \frac{1}{2} } \\ \\ \huge \: \red {y(t) = \sqrt{2t + 1 } } \\ \\b) \: \: plug \: y(t) = 2 \: in \: above \: equation \\ \\ 2 = \sqrt{2t + 1} \\ \\ 4 = 2t + 1 \: \\ (squaring \: both \: sides) \\ \\ 4 - 1 = 2t \\ \\ 2t = 3 \\ \\ t = \frac{3}{2} \\ \\ t = 1.5 \: hours \\$

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2 years ago

An architect makes a model of a new house. The model shows a tile patio in the backyard. In the​ model, each tile has length

An architect makes a model of a new house. The model shows a tile patio in the backyard. In the model, each tile has length