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3 years ago

I will rate you branliest

Mathematics

2 answers:

nadezda [96]3 years ago

7 0

Answer:

a₃ = 9

Step-by-step explanation:

The numbers in the set are referred to as { a₁, a₂, a₃, ... }

Reptile [31]3 years ago

7 0

Answer:

<h3>a3 = 9 is the answer to this question </h3>

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I like to put these in the form f(x) = 0. We can do that by subtracting the right side. Common factors can be cancelled from numerator and denominator, provided they are not zero.

$\dfrac{7}{x+3}+\dfrac{3}{x-3}-\dfrac{x}{x-3}=0\\\\ \dfrac{7(x-3)+(x+3)(3-x)}{(x+3)(x-3)}=0\\\\\dfrac{(x-3)(4-x)}{(x-3)(x+3)}=0\\\\ \dfrac{4-x}{x+3}=0\qquad x\ne3\\\\x=4 \qquad\text{equate the numerator to zero, add $x$}$

_____

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