All categories

2 years ago

1. Write an equation in point-slope form of the line that that passes through the point (4,-5) and has a

Mathematics

1 answer:

Aleks04 [339]2 years ago

7 0

Answer:

y + 5 = (3/2)(x - 4)

Step-by-step explanation:

The point-slope formula is y - k = m(x - h). We get h and k from the given point: h = 4 and k = -5, and m from the given slope: 3/2. Then we have:

y + 5 = (3/2)(x - 4)

You might be interested in

Hi What is the area of the object above?

WINSTONCH [101]

Dieikenfjdj dodkfkdkd dkdkfkdndd disk djdkd

7 0

2 years ago

(Divide the following polynomials (x5 + y5) ÷ (x + y)

stiks02 [169]

$\text{Use}\ a^5+b^5=(a + b) (a^4 - a^3 b + a^2 b^2 - a b^3 + b^4).\\\\(x^5+y^5):(x+y)=\dfrac{x^5+y^5}{x+y}=\dfrac{(x+y)(x^4-x^3y+x^2y^2-xy^3+y^4)}{x+y}\\\\=\boxed{x^4-x^3y+x^2y^2-xy^3+y^4}$

7 0

3 years ago

Which property of equality should be used with the equation c + 5 = 78 to solve?

rjkz [21]

Answer:

Subtraction property of equality

Step-by-step explanation:

c + 5 = 78

Subtract 5 from each side using the subtraction property of equality

c+5-5 = 78-5

x = 73

5 0

2 years ago

A luxury liner leaves a port on a bearing of 110 degrees and travels 8.8 miles. It then turns due west and travels 2.4 miles. Ho

myrzilka [38]

Answer:

Distance= 6.6 miles

Bearing= N 62.854°W

Step-by-step explanation:

Let's determine angle b first

Angle b=20° (alternate angles)

Using cosine rule

Let the distance between the liner and the port be x

X² =8.8²+2.4²-2(8.8)(2.4)cos20

X²= 77.44 + 5.76-(39.69)

X²= 43.51

X= √43.51

X= 6.596

X= 6.6 miles

Let's determine the angles within the triangle using sine rule

2.4/sin b = 6.6/sin20

(2.4*sin20)/6.6= sin b

0.1244 = sin b

7.146= b°

Angle c= 180-20-7.146

Angle c= 152.854°

For the bearing

110+7.146= 117.146

180-117.146= 62.854°

Bearing= N 62.854°W

8 0

3 years ago

Write an equation in slope-intercept form of the line that bisects the angle formed by BA and BC

slega [8]

Given:

Angled formed by ray BA and ray BC is 90 degrees.

To find:

The equation of line that bisects the angle formed by ray BA and ray BC.

Solution:

If a line bisects the angle formed by ray BA and ray BC, then it must be passes through point B and makes angles of 45 degrees with ray BA and ray BC.

It is possible if the line passes though point B(-1,3) and other point (-2,4).

Equation of line is

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$