Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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Answer:
I believe the answer is 9
Step-by-step explanation:
The most balloons she has is 180 and she can make 20 animals with that so 180/20=9
We can treat this problem like you regularly subtract fractions. First find the common denominator, which is 15.
So:
5(x+6)/15 = 30/15 + 3(x-2)/15
(5x+6)/15 - (30/15) - (3x - 6)/15
As you already know the answer, I'm assuming you can do the rest.
Hope this helps!
Answer:
12.
Step-by-step explanation:
Replace k in the radical by -2:
So we have √(-72*-2)
= √144
= 12.
Definitely.
But the two numbers have to be 6 and zero.
