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3 years ago

Find exact value for cos(pi/16)

Mathematics

1 answer:

stellarik [79]3 years ago

6 0

The exact value for cos(pi/16) would be :

cos (pi/16) = +/- √1+cosa/2

cos (pi/4) = sqrt2/2

Hope this helps

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3 1/5 less than 1, equal to 1, or greater than 1?

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Answer:

Greater than 1

Step-by-step explanation:

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3 years ago

Matt bought some boards to build a wooden deck. Some of the boards were 4 ft long and some of the boards were 5 ft long. He boug

Kazeer [188]

Answer:

8 boards.

Step-by-step explanation:

Since he bought a few of each length. The only combination that works is when he bought 5 of the 4 ft long board so 4×5=20. Than he bought 3 of the 5ft boards 3×5=15. 20+15=35 ft worth of boards.

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3 years ago

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I need help with this simple math problem. ^_^

mote1985 [20]

Answer:

The answer to this question is A

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A won a race at the local fair by running 10.5 miles in exactly 2 hours. At this constant rate, how long does it take the same

Luba_88 [7]

Answer:

The dog will run the 21-mile race in 4.04 hours

Step-by-step explanation:

The first thing we need to do is find out how far he ran the race at the local fair in 1 hour.

To do this, we can set up a simple relationship:

If he ran 10.5 miles in 2 hours,

He will run x miles in 1 hour

Cross multiplying, we have

x = (10.5 X 1)/2 = 5.25 miles in 1 hour.

We can now comfortably say that he runs at the rate of 5.2miles/hr

He now goes to the state fair race, which is 21 miles long.

if he runs at the rate of 5.2 miles in 1 hour,

He will run 21 miles in y hours

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The dog will run the 21-mile race in 4.04 hours

3 0

3 years ago

I built a storage shed in the shape of a rectangular box on a square base. The material that I used for the base cost $4 per squ

kumpel [21]

Answer:

side of 6.124 ft and height of 3.674 ft

Step-by-step explanation:

Let's s be the side of the square base and h be the height of the rectangular box.

The base and the roof would have an area of $s^2$ and cost of

$4s^2 + 2s^2 = 6s^2$

The sides would have an area of 4sh and cost of 4sh*2.5 = 10sh

So the total cost for the material is

$6s^2 + 10sh = 450$

$10sh = 450 - 6s^2$

$h = 45/s - 0.6s$

The volume of the shed has the following formula

$V = s^2h = s^2(45/s - 0.6s) = 45s - 0.6s^3$

To find the maximum value for V, we can take its first derivative, and set it to 0

$\frac{dV}{ds} = 45 - 1.2s^2 = 0$

$1.2s^2 = 45$

$s^2 = 45 / 1.2 = 37.5$

$s = \sqrt{37.5} = 6.124 ft$

h = 45/s - 0.6s = 3.674 ft

4 0

4 years ago