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3 years ago

PLEASE HELP ASAP WITH MATH QUESTION WHAT IS (-image down below-) EQUAL TO?????

Mathematics

2 answers:

PolarNik [594]3 years ago

8 0

Answer:

1364

Step-by-step explanation:

∑ means that to add values

So n goes from 1 to 5 and you have to add them from 1 to 5

∑n=1 to 5 4^n = 4^1 + 4^2 + 4^3 + 4^4 + 4^5

4^n means that 4 is n times if 4^3 its mean that 4 is 3 times

= 4 + 16 + 64 + 256 + 1024

= 1364 Answer

I hope you got the idea. Thanks

vlabodo [156]3 years ago

8 0

Answer:

The series is equal to 1364

Step-by-step explanation:

You have a series there ...

A series is the sum of a series of values

If it starts at n = 1 and ends at n = 5 then it substitutes the values and adds:

4 ^ 1 + 4 ^ 2 + 4 ^ 3 + 4 ^ 4 + 4 ^ 5

= 4 + 16 + 64 + 256 + 1024

= 1364

Finally the series is equal to 1364

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forsale [732]

Answer:

if you got paid seven bucks per lawn, and you mowed nine lawns, you'd have $63 dollars

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3 years ago

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3 years ago

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A ball is chosen at random from a bag containing 150 balls that are either red or blue and either dull or shiny. There are 36 re

tino4ka555 [31]

Answer:

The probability of the chosen ball being shiny conditional on it being red is; 0.375

Step-by-step explanation:

Let A be the event that a red ball has been chosen

Let B be the event that a shiny ball has been chosen

Let S be the total outcomes = 150 balls

Thus;

P(A ∩ B ) = 36/150

A ∩ B' = 150 - 36 - 54

A ∩ B' = 60

Thus; P(A ∩ B') = 60/150

P(A') = 54/150

P(A) = (150 - 54)/150 = 96/150

Thus, probability of the chosen ball being shiny conditional on it being red is;

P(B | A) = P(B ∩ A)/P(A)

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2 years ago

Need help on 15 and 16 PLEASEE!!!

melisa1 [442]

Answer:

Part 15) The next three terms are 5/8,3/4 and 7/8

Part 16) The 37th term is -35.5

Step-by-step explanation:

we know that

In an Arithmetic Sequence the difference between one term and the next is a constant and this constant is called the common difference (d)

Part 15) Find the next three terms of the arithmetic sequence

$\frac{1}{8},\frac{1}{4},\frac{3}{8},\frac{1}{2},...$

$a1=1/8\\ a2=1/4\\ a3=3/8\\ a4=1/2\\ a2-a1=1/4-1/8=1/8\\ a3-a2=3/8-1/4=1/8\\ a4=a3=1/2-3/8=1/8$

The common difference is equal to

d=1/8

Find the next three terms of the arithmetic sequence

Find a5

$a5=a4+d$ -----> $a5=1/2+1/8=5/8$

Find a6

$a6=a5+d$ -----> $a6=5/8+1/8=3/4$

Find a7

$a7=a6+d$ -----> $a7=3/4+1/8=7/8$

therefore

The next three terms are

5/8,3/4 and 7/8

Part 16) what is the 37th term of the arithmetic sequence

$4.1,3,1.9,0.8,...?$

$a1=4.1\\ a2=3\\ a3=1.9\\ a4=0.8$

$a2-a1=3-4.1=-1.1\\ a3-a2=1.9-3=-1.1\\ a4=a3=0.8-1.9=-1.1$

The common difference is equal to

d=-1.1

We can write an Arithmetic Sequence as a rule

$an=a1+d(n-1)$

substitute the values

$an=4.1-1.1(n-1)$

For n=37

substitute

$a37=4.1-1.1(37-1)$

$a37=4.1-1.1(36)$

$a37=-35.5$

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3 years ago

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Answer:

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Step-by-step explanation:

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