Answer:
2a^2b(5a-3b)
If not then the other way is
5a-3b
Step-by-step explanation:
The GCF of 10a^3b and -6a^2b^2 is 2a^2b
So divide by that you will get
2a^2b(5a-3b)
-2, -3, -4.
an integer is a number that isn't a fraction. so literally any natural number like 1, 0, or -1. all integers.
3/7 is the answer for this question
The probability that a 2 or 3 is rolled at least once is 0.14.
<h3>
Probability of not rolling a 2 or 3 in a single die roll of two dice</h3>
when a six die is rolled once there is 11/12 probability of not rolling 2 or 3.
rolling a six sided die two times, p(2 or 3)' = 11/12
rolling a six sided die four times, p(2 or 3)' = (11/12)² = 121/144
the probability that a 2 or 3 is rolled at least once is calculated as follows;
P = 1 - p(2 or 3)'
P = 1 - 121/144
P = 20/144
P = 0.14
Thus, the probability that a 2 or 3 is rolled at least once is 0.14.
Learn more about probability here: brainly.com/question/24756209
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Answer:
1/9 = 0.11111111 ( infinite )
Step-by-step explanation: