All categories

3 years ago

When 40% of a number is added to the number, the result is 140. What is the number ?

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

8 0

$x-searched\ number\\\\40\%x+x=140\\\\0.4x+x=140\\\\1.4x=140\ \ \ \ \ |:1.4\\\\x=100\\\\The\ number\ is\ 100$

You might be interested in

The table below represents an exponential function what is the common ratio

Greeley [361]

Solution:

Given:

A table representing an exponential function.

The x-values represent the terms, while the y-values represent the numbers.

The common ratio is gotten from the numbers (y-values).

The formula for common ratio is given by;

$\begin{gathered} r=\frac{present\text{ term}}{preceed\text{ ing term}} \\ \\ \text{Hence,} \\ r=\frac{108}{36}=\frac{36}{12}=\frac{12}{4}=\frac{4}{1.33\ldots}=\frac{1.33\ldots.}{0.44\ldots} \\ r=3 \end{gathered}$

Therefore, the common ratio is 3.

3 0

2 years ago

Jim needs to rent a car. A rental company charges $21.0 per day to rent a car. and $0.10 for every mile driven. He will travel 2

olga nikolaevna [1]

Answer:

He cant rent the car for 5 days

Step-by-step explanation:

21 * 5 = 105

0.10 * 250 = 25

105 + 25 = 130

He only has 115 to spend

7 0

3 years ago

Read 2 more answers

A playground is being designed where children can interact with their friends in certain combinations. If there is 1 child, ther

mariarad [96]

<h2>Answer:</h2>

Recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

<h2>Step-by-step explanation:</h2>

In the question,

The number of interaction for 1 child = 0

Number of interactions for 2 children = 1

Number of interactions for 3 children = 5

Number of interaction for 4 children = 14

So,

We need to find out the pattern for the recursive equation for the given conditions.

So,

We see that,

$a_{1}=0\\a_{2}=1\\a_{3}=5\\a_{4}=14\\$

Therefore, on checking, we observe that,

$a_{n}=a_{n-1}+(n-1)^{2}$

On checking the equation at the given values of 'n' of, 1, 2, 3 and 4.

At,

n = 1

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{1}=a_{1-1}+(1-1)^{2}\\a_{1}=0+0=0\\a_{1}=0$

which is true.

At,

n = 2

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{2}=a_{2-1}+(2-1)^{2}\\a_{2}=a_{1}+1\\a_{2}=1$

Which is also true.

At,

n = 3

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{3}=a_{3-1}+(3-1)^{2}\\a_{3}=a_{2}+4\\a_{3}=5$

Which is true.

At,

n = 4

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{4}=a_{4-1}+(4-1)^{2}\\a_{4}=a_{3}+9\\a_{4}=14$

This is also true at the given value of 'n'.

Therefore, the recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

3 0

3 years ago

Last month, at a tax free sale, joy bought 4 new blouses that cost $15.95 each and 2 new belts that cost $8.95 each. How much di

Olenka [21]

Answer:

$81.70

Step-by-step explanation:

15.95 x 4 = 63.80

8.95 x 2 = 17.90

63.80 + 17.90

8 0

3 years ago

Two trains leave the same station at the same time, but are headed in opposite directions. One train travels at 70 mph and the o

mamaluj [8]

70h+80h=600
150h=600
h = 4 hours answer C

4 0

4 years ago