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WARRIOR [948]
3 years ago
11

Last month, at a tax free sale, joy bought 4 new blouses that cost $15.95 each and 2 new belts that cost $8.95 each. How much di

d joy pay for her purchase?
Mathematics
1 answer:
Olenka [21]3 years ago
8 0

Answer:

$81.70

Step-by-step explanation:

15.95 x 4 = 63.80

8.95 x 2 = 17.90

63.80 + 17.90

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We will use double angle identities:
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cos ( 5 x) - 2 cos ( 5 x ) sin ( 5x ) = 0
cos ( 5 x ) · [ 1 - 2 sin (5 x) ] = 0
cos ( 5 x ) = 0                    or :       1 - 2 sin (5 x) = 0
5 x = π/2 +kπ,  k∈Z                        sin (5 x) = 1/2
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4 0
3 years ago
Sue has 18 sweets. Tony also has 18 sweets. Sue gives Tony x sweets. Sue then eats 5 of her sweets. Tony then eats half of his s
Ede4ka [16]
Answer is below.........

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4 years ago
-2 -13.8x = -8 -(6x+1)
Varvara68 [4.7K]
-2 -13.8x = -8 -6x -1
First, I distributed the negative 1 that was outside of the parentheses to the positive 6x and the positive 1.

-2 -13.8x = -9 -6x
Then I added the negative 8 to the negative 1 which equals negative 9.

-2 -13.8x +6x = -9 -6x +6x
After that I used the addition property and added a positive 6x to both sides.

-2 -7.8x = -9
Then simplifying.

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After simplifying, I used the addition property again, adding a positive 2 to both sides.

-7.8x = -7
Simplified.

-7.8x (-1) = -7 (-1)
Then I multiplied both sides by with a negative 1 since the variable cannot be a negative.

7.8x = 7
Simplified

(1/7.8) 7.8x = (1/7.8) 7
Then, to isolate the veriable, I multiplied 1/7.8 to both sides.

x = 1.11428571429
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I hope this helped !
7 0
3 years ago
The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is
marysya [2.9K]

Answer:

(a) 0.14%

(b) 2.28%

(c) 48%

(d) 68%

(e) 34%

(f) 50%

Step-by-step explanation:

Let <em>X</em> be a random variable representing the prices paid for a particular model of HD television.

It is provided that <em>X</em> follows a normal distribution with mean, <em>μ</em> = $1600 and standard deviation, <em>σ</em> = $100.

(a)

Compute the probability of buyers who paid more than $1900 as follows:

P(X>1900)=P(\frac{X-\mu}{\sigma}>\frac{1900-1600}{100})

                   =P(Z>3)\\=1-P(Z

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid more than $1900 is 0.14%.

(b)

Compute the probability of buyers who paid less than $1400 as follows:

P(X

                   =P(Z

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid less than $1400 is 2.28%.

(c)

Compute the probability of buyers who paid between $1400 and $1600 as follows:

P(1400

                              =P(-2

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1400 and $1600 is 48%.

(d)

Compute the probability of buyers who paid between $1500 and $1700 as follows:

P(1500

                              =P(-1

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1500 and $1700 is 68%.

(e)

Compute the probability of buyers who paid between $1600 and $1700 as follows:

P(1600

                              =P(0

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1600 and $1700 is 34%.

(f)

Compute the probability of buyers who paid between $1600 and $1900 as follows:

P(1600

                              =P(0

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1600 and $1900 is 50%.

8 0
3 years ago
Solve for 2. Round to the nearest tenth of a degree, if necessary, 7.2 D 10 9.4. B​
Lelechka [254]

Answer:

x=50°

use the sine rule to find the missing angle "x"

4 0
3 years ago
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