Hi there!
Let th' two number be ' a ' and ' b ' [ a > b ]
According to th' question :-
→ The largest of two numbers is 12 more than the smaller number.
a = 12 + b ---(i)
→ Sum of the two numbers is 74.
a + b = 74
b = 74 - a ---(ii)
Substitute th' value of ' b in Eqn. :-
a = 12 + (74 - a)
a = 86 - a
a + a = 86
2a = 86
a =

= 43
Now,
Substitute th' value of ' a ' in Eqn. (ii)
b = 74 - b
b = 74 - 43
b = 31
Hence,
The required answer is :-
• The smaller number is 31
• The largest number is 43
~ Hope it helps!
Answer:
Step-by-step explanation:
27 ) 2x² - x - 1 = 0
2x² - 2x + x - 1 = 0
2x ( x - 1) + (x - 1) = 0
(x - 1)(2x + 1) = 0
x - 1 = 0 ; 2x + 1 = 0
x = 1 ; 2x = -1
x = -1/2
x = 1 ; -1/2
Option b
28) Area of a rectangle = 24 cm²
length * width = 24
(3x +2 )(2x -1) = 24
3x(2x -1) + 2(2x - 1) = 24
3x *2x - 3x *1 + 2*2x - 2*1 = 24
6x² -3x + 4x - 2= 24
6x² + x - 2 -24 = 0
6x² + x - 26 = 0
6x² -12x + 13x - 26 = 0
6x(x - 2) + 13(x - 2) = 0
(x -2)(6x +13) = 0
x = 2 {Ignore 6x + 13 as it gives negative value}
length = 3x + 2 = 3*2 + 2 = 6 + 2 = 8 cm
Width = 2x - 1 = 2*2 - 1 = 4 - 1 = 3 cm
29) Area of square = 900 cm²
Side² = 900
(5x)² = 900
25x² = 900
x² = 900/25
x² = 36
x = √36 = √6*6
x = 6 cm
30) base = b cm
height = b + 2
Area of triangle = 24 cm²

b(b + 2) = 24*2
b² + 2b = 48
b² + 2b - 48 = 0
b² - 6b + 8b - 48 = 0
b(b - 6) + 8(b - 6) = 0
(b - 6) (b + 8) = 0
b - 6 = 0 {Ignore b +8 = 0 as it gives negative value}
b = 6 cm
height = 6+ 2 = 8 cm
2 .............:)
Good luck
Answer:
12
Step-by-step explanation:
12 because that's how many dots/vertices are shown(sorry if im wrong)
Answer:
no
Step-by-step explanation:
the sum of 4+7+9+12=32
32/4= 8
8 is not part of the sequence. Therefore its not arithmetic.