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lutik1710 [3]
3 years ago
10

How do I simplify the expression 2-^1/3 times 2^7/3 A. 64 B. 1/4 C. 4 D. 8

Mathematics
1 answer:
mihalych1998 [28]3 years ago
8 0

Answer:

C.4

Step-by-step explanation:

Since the values are of the same base....

we add the powers..because its multiplication...

;2^(-1/3 + 7/3)

;2^(6/3) = 2^2

;Ans = 2^2 = 4

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Factorise x squared + 3x + 2​
Zielflug [23.3K]

Answer:

(x + 2)(x + 1)

Step-by-step explanation:

by factorising ;

=》

{x}^{2}  + 3x  + 2

=》

{x}^{2}  + 2x + x + 2

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x(x + 2) + 1(x + 2)

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(x + 2)(x + 1)

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8 0
3 years ago
1) What is the solution of the given system?
m_a_m_a [10]

Answer:

1  x=-2.5  y = -5.5

2.  x=5  y=1

Step-by-step explanation:

1) What is the solution of the given system?

5x-y=-7

3x-y=-2

Multiply the second equation by -1

-1*(3x-y)=-1(-2)

-3x +y = 2


Now add the first equation to the modified second equation

5x-y=-7

-3x +y = 2

------------------

2x = -5

Divide each side by 2

2x/2 = -5/2

x = -2.5

Now we need to find y

-3x+y =2

-3(-2.5) +y =2

7.5 +y =2

Subtract 7.5 from each side

7.5 -7.5 +y =2-7.5

y = -5.5


2) what is the solution of the given system?

5x+7y=32

8x+6y=46

Divide the second equation by 2

8x/2+6y/2=46/2

4x+3y =23


Multiply the first equation by 4

4 (5x+7y)=32*4

20x+28y = 128


Now multiply the modified 2nd equation by -5

-5(4x+3y )=-5(23 )

-20x -15y = -115


Lets add the new equations together to eliminate x

20x+28y = 128

-20x -15y = -115

---------------------

      13y = 13

Divide each side by 13

13y/13 =13/13

y=1

Now substitute back in to find x

5x+7y=32

5x +7(1) =32

5x +7 =32

Subtract 7 from each side

5x+7-7 =32-7

5x =25

Divide by 5

5x/5 =25/5

x=5





3 0
3 years ago
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