d) You have a <u>difference of squares</u>:
49y² - 9 = (7y)² - 3²
Recall the identity,
a² - b² = (a - b) (a + b)
So,
49y² - 9 = (7y - 3) (7y + 3)
e) Pull out the common factor 3 from each term:
3x² - 3x - 90 = 3 (x² - x - 30)
Now use the <u>sum-product method</u>. Notice that we can write 30 = 5 • 6, and 5 - 6 = 1, so
3x² - 3x - 90 = 3 (x + 5) (x - 6)
f) Same as in (e), use the <u>sum-product method</u>. Notice that 42 = 7 • 6, and -7 - 6 = -13, so
x² - 13x + 42 = (x - 7) (x - 6)
A minus x plus b equals c
Answer:
angle 1 and angle 7
Step-by-step explanation:
If two lines intersected by a transversal form supplementary same-side interior angles, then the lines are parallel.
Hello there! The answer is the first option, 31/55.
To solve this, we don't even need to do any math. Note that fractions with the same numerator and denominator will be equal to 1.
Knowing this and looking at our second and fourth options, 55/55 x 111 and 31/31 x 111, these problems are the same as 1 x 111, which results in 111, which is not less than, leaving us with the third and first options.
The third option is 55/31, meaning we have more than a whole, so we are multiplying by a number greater than 1, making our answer over 111 and this option not correct.
This leaves the first option as your answer!
Assuming that the fee is purely based on duration, the equation would look like this:
c= a*p
where c= cost, a= rates per hour, p= hours of parking
Alexandra pays 7$ for 3 hours parking. So, a would be:
c= a*p
7$= a * 3 hr
a= 7$/3hr
Then the final equation would be:
c= (7/3) *p
