Solve for X on both equations
2x - 2 < -12
Add two on both sides
2x < -10
Divide by two on both sides
2 < -5
2x + 3 > 7
Subtract three on both sides
2x > 4
Divide by two on both sides
x > 2
A. x < -5 or x > 2
Answer:
y = x + 1
Step-by-step explanation:
We are using the points (0, 1) and (6, 7). First, use these points to find the slope.
m = y₁ - y₂/x₁ - x₂
⇒ m = 7 - 1/6 - 0
⇒ m = 6/6
⇒ m = 1
Now that we know the slope is one, enter the values into the point-slope form equation. I'll use (0, 1) in this instance.
y - y₁ = m(x - x₁)
⇒ y - 1 = 1(x - 0)
⇒ y - 1 = x
⇒ y = x + 1
Therefore, the equation is y = x + 1.
The answer to your question is 11
Answer:
x = 3 ±sqrt(6)
Step-by-step explanation:
6(x-3)^2-26 = 10
Add 26 to each side
6(x-3)^2-26+26 = 10+26
6(x-3)^2 = 36
Divide by 6
6/6(x-3)^2 = 36/6
(x-3)^2 = 6
Take the square root of each side
sqrt((x-3)^2) = ±sqrt(6)
x-3 = ±sqrt(6)
Add 3 to each side
x-3+3 =3 ±sqrt(6)
x = 3 ±sqrt(6)
The answer is B as it is the only one that matches the 2 inequalities.
