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Degger [83]
3 years ago
7

A(x+y)-a(x-y) simplified .

Mathematics
2 answers:
Keith_Richards [23]3 years ago
7 0

Answer:

2ay

Step-by-step explanation:

a(x+y)-a(x-y)

Distribute

ax +ay - ax + ay

Combine like terms

2ay

Mrrafil [7]3 years ago
6 0
<h3>Answer:   2ay</h3>

Work Shown:

a(x+y)-a(x-y)

ax+ay-ax+ay

(ax-ax)+(ay+ay)

(0ax)+(2ay)

0+2ay

2ay

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Find the distance between (16,12) and (0,0)
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Answer:

3/4 using equation y2-y1/x2-x1

Step-by-step explanation:

Use the equation y2-y1/x2-x1

x1, y1  x2, y2

(16,12) (0,0)

0-12/0-16= -12/-16= 3/4

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3 years ago
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5 because 25 divided by 5 is 5
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3 years ago
A manager of a grocery store wants to determine if consumers are spending more than the national average. The national average i
strojnjashka [21]

The valid conclusions for the manager based on the considered test is given by: Option

<h3>When do we perform one sample z-test?</h3>

One sample z-test is performed if the sample size is large enough (n  > 30) and we want to know if the sample comes from the specific population.

For this case, we're specified that:

  • Population mean = \mu = $150
  • Population standard deviation = \sigma = $30.20
  • Sample mean = \overline{x} = $160
  • Sample size = n = 40 > 30
  • Level of significance = \alpha = 2.5% = 0.025
  • We want to determine if the average customer spends more in his store than the national average.

Forming hypotheses:

  • Null Hypothesis: Nullifies what we're trying to determine. Assumes that the average customer doesn't spend more in the store than the national average. Symbolically, we get: H_0: \mu_0 \leq \mu = 150
  • Alternate hypothesis: Assumes that customer spends more in his store than the national average. Symbolically H_1: \mu_0 > \mu = 150

where \mu_0 is the hypothesized population mean of the money his customer spends in his store.

The z-test statistic we get is:

z = \dfrac{\overline{x} - \mu_0}{\sigma/\sqrt{n}} = \dfrac{160 - 150}{30.20/\sqrt{40}} \approx 2.094

The test is single tailed, (right tailed).

The critical value of z at level of significance 0.025 is 1.96

Since we've got 2.904 > 1.96, so we reject the null hypothesis.

(as for right tailed test, we reject null hypothesis if the test statistic is > critical value).

Thus, we accept the alternate hypothesis that customer spends more in his store than the national average.

Learn more about one-sample z-test here:

brainly.com/question/21477856

3 0
1 year ago
Read 2 more answers
You are standing at point p use the drop down menus to identify the path you must follow to get to the gardens
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Answer:

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Step-by-step explanation:

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