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Degger [83]
3 years ago
7

A(x+y)-a(x-y) simplified .

Mathematics
2 answers:
Keith_Richards [23]3 years ago
7 0

Answer:

2ay

Step-by-step explanation:

a(x+y)-a(x-y)

Distribute

ax +ay - ax + ay

Combine like terms

2ay

Mrrafil [7]3 years ago
6 0
<h3>Answer:   2ay</h3>

Work Shown:

a(x+y)-a(x-y)

ax+ay-ax+ay

(ax-ax)+(ay+ay)

(0ax)+(2ay)

0+2ay

2ay

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Find the perimeter of ABCD<br> Find the area of Area
san4es73 [151]

Step-by-step explanation:

A = (1, 3)

B = (3, 6)

C = (9, 2)

D = (7, -1)

the distance between 2 points is given by the Pythagoras equation based on the coordinate differences as legs of virtual right-angled triangles.

AD for example we get from

AD² = (7-1)² + (-1 - 3)² = 6² + (-4)² = 36 + 16 = 52

AD = sqrt(52) = sqrt(4×13) = 2×sqrt(13)

and AB we get from

AB² = (3-1)² + (6-3)² = 2² + 3² = 4 + 9 = 13

AB = sqrt(13)

the perimeter of the given rectangle is

2×sqrt(52) + 2×sqrt(13) = 2×2×sqrt(13) + 2×sqrt(13) =

= 6×sqrt(13) = 21.63330765...

and the area of the rectangle is

2×sqrt(13)×sqrt(13) = 2×13 = 26

7 0
2 years ago
Which of the following equations matches the function shown above?
Ksenya-84 [330]

So, the function is obviously shifted up by 1 so it rules out A and B, and we also see that the period is 4pi rather than 2pi, and using the fact that:

\frac{2\pi}{b}=4\pi \implies \frac{b}{2\pi}=\frac{1}{4\pi}\implies b=\frac{1}{2}

Now that we know our b value, we see that the correct answer would be C.

3 0
3 years ago
3 1/3 x 3 =??<br> Not quite understanding
marishachu [46]

Answer:

10

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
HbhhhhvbvbbhHzhzhhshhjzjzbsjzjsjjsujenwja
sineoko [7]

Answer:

hgfhdgsgzfzsgfzgzfffdfdsfdfgfghgf

Step-by-step explanation:

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6 0
2 years ago
Me. Ellis is a teacher who tutors after school. Of the students he tutors, 30% need help in computer science and 70% need assist
Anna11 [10]

Answer: There are 82.5% after school students who are enrolled in his classes.

Step-by-step explanation:

Let the total number of students be 100

Percentage of students who need help in computer science = 30%

So, number of students who need help in computer science = 30

Percentage of students who need help in maths = 70%

So, number of students who need assistance in maths  = 70

Of the students who need help,

40% are enrolled in Mr. Ellis's class during the school day,

So, it means 60% are enrolled in his class after the school day.

Number of students who are enrolled in his class after the school day = 60

Number of students who need help in Maths is given by

\frac{70}{100}\times 60=42

Of the students that need help in maths, percent of students are enrolled in his class during the day = 25%

So, number of students who need help in maths and enrolled in his class after school hours

\frac{75}{100}\times 42=31.5

Number of students who need help in computer science and enrolled in his class after school hours

\frac{30}{100}\times 60=18

Therefore, there are 31.5+18=49.5 students who joined his class after school hours,

Percentage of the after students who are enrolled in Mr. Ellis's classes is given by

\frac{49.5}{60}\times 100=82.5\%

Hence, there are 82.5% after school students who are enrolled in his classes.


6 0
4 years ago
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