Answer:
I live in a rural area which is surrounded by mountains and valleys. Near my home there is small forest area where there are hundreds of thick tall forests, algae and many other photosynthetic plants.
The atmosphere of that forest is very clean and refreshing because there is alot of oxygen being produced there due to alot of photosynthesis being done by all the lush green plants there.
Due to photosynthesis, carbon di oxide that is an environmental pollutant is maximum used by the plants and maximum. Oxygen is produced as a result of photosynthesis.
This causes the environment of not only that forest but my whole village very clean and fresh to breath. We are living a healthy life where there is a less prevalence of diseases or infections that are caused by environmental pollutants like Bronchitis, Lungs infection, neural disorders etc.
Therefore, even if there is not such an area near your home, we would suggest you to plant more trees in your backyard that will make the environment of not only your home but your area very fresh and clean.
Hope it help!
The tilt of the earth's axis, which essentially "turns" certain parts of earth so that some parts receive more direct sunlight
Essentially wetlands<span> are the transition </span>between<span> dry land and water (streams, </span>rivers,lakes<span>, and coastlines), </span>wetlands<span> take many forms including the familiar marshes, swamps and bogs. Yet, not all </span>wetlands<span> are "wet" year round. These "drier end"</span>wetlands<span> also perform significant </span>wetland<span> functions.
Hope i helped :)</span>
Answer:
Frequency of CW allele in the population= 0.41
Explanation:
A diploid organism has two alleles for each gene. So, a population of 100 plants will have total 100 x 2 = 200 alleles.
The each of the white colored plants have two copies of CW alleles and each pink flowered plant have only one CW allele.
Frequency of CW allele in the population = total number of white flowered plants x 2 + total number of pink colored plants / total population size x 2.
Frequency of CW allele in the population= 22 x 2 + 38 / 100 x 2 = 82 /200 = 0.41
