All categories

3 years ago

Which is the correct input-output table for the function f(x) = 7 – 4.5x?

Mathematics

2 answers:

DanielleElmas [232]3 years ago

7 0

Input (x): 1 3 4 6 10

Output f(x): 2.5 -6.5 -11 -20 -38

*Answer B on PLATO

Naddika [18.5K]3 years ago

3 0

Step 1: Divide both sides by x.fxx=−4.5x+7xf=−4.5x+7xAnswer:f=−4.5x+7x

You might be interested in

PLEASE HELP ME 50 POINTS!!!

Irina-Kira [14]

Answer:

it's 13a+2 pal!

Step-by-step explanation:

3 0

3 years ago

PLZ SOME ONE HELPS QUICK ILL GIVE 50 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!

neonofarm [45]

We already know that the distance of all the planets are generally calculated by keeping the Sun as the main location point.
Explanation:
The distances of all the planets from the Sun in scientific notation and exponential form-
Mercury-
57
million kilometers.
Scientific notation-
5.7
⋅
10
7

km

Venus-
108
million kilometers.
Scientific notation-
1.08
⋅
10
8

km

Earth-
150
million kilometers
Scientific notation-
1.5
⋅
10
8

km

Mars-
228
million kilometers
Scientific notation-
2.28
⋅
10
8

km

Jupiter-
779
million kilometers
Scientific notation-
7.79
⋅
10
8

km

Saturn-
1.43
billion kilometers
Scientific notation-
1.43
⋅
10
9

km

Uranus-
2.88
billion kilometers
Scientific notation-
2.388
⋅
10
9

km

Neptune-
4.5
billion kilometers
Scientific notation-
4.5
⋅
10
9

km

8 0

3 years ago

Which number represents a square root of 3 (cosine (StartFraction pi Over 2 EndFraction) + I sine (StartFraction pi Over 2 EndFr

wariber [46]

Answer: hello your question is poorly written attached below is the complete question

answer:

$\sqrt{3}(cos(\frac{3\pi }{2}) + isin(\frac{3\pi }{2}))$ --- ( option d )

Step-by-step explanation:

The correct option that represents a square root of 3 as related to the question attached below is :

$\sqrt{3}(cos(\frac{3\pi }{2}) + isin(\frac{3\pi }{2}))$

8 0

3 years ago

How many permutations of the 26 letters of the English alphabet do not contain any of the strings fish, rat, or bird

NARA [144]

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

$\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}$

Then

$Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\$

Note that since

$F \cap R=\varnothing$ , $Perm(F)\cap Perm(R)\ne \varnothing$

But since

$B \cap R \ne \varnothing$ , $Perm(B)\cap Perm(R)= \varnothing$

and

$B \cap F \ne \varnothing$ , $Perm(B)\cap Perm(F)= \varnothing$

Since

$|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\$

where $|Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}$

and

$|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}$

What we are looking for is the number of permutations of the 26 letters of the alphabet that do not contain the strings fish, rat or bird, or

$|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}$

This link contains another solved problem on permutations:

brainly.com/question/7951365

6 0

2 years ago

What is (2+y)³ written out?

Aleksandr-060686 [28]

${ \left( 2+y \right) }^{ 3 }\\ \\ =\left( 2+y \right) \left( 2+y \right) \left( 2+y \right) \\ \\ =\left( 2+y \right) \left( 4+4y+{ y }^{ 2 } \right)$

$\\ \\ =2\left( 4+4y+{ y }^{ 2 } \right) +y\left( 4+4y+{ y }^{ 2 } \right) \\ \\ =8+8y+2{ y }^{ 2 }+4y+4{ y }^{ 2 }+{ y }^{ 3 }\\ \\ ={ y }^{ 3 }+6{ y }^{ 2 }+12y+8$

5 0

3 years ago