Answer:
It's 8
Step-by-step explanation:
![16 ^{ \frac{3}{4} } = \sqrt[4]{16 ^{3} } = \sqrt[4]{2 ^{4 \times 3} } = 2^{ \frac{12}{4} } = 2^{3} = 8](https://tex.z-dn.net/?f=%2016%20%5E%7B%20%5Cfrac%7B3%7D%7B4%7D%20%7D%20%20%3D%20%20%5Csqrt%5B4%5D%7B16%20%5E%7B3%7D%20%7D%20%20%3D%20%20%5Csqrt%5B4%5D%7B2%20%5E%7B4%20%5Ctimes%203%7D%20%7D%20%3D%202%5E%7B%20%5Cfrac%7B12%7D%7B4%7D%20%7D%20%20%20%3D%202%5E%7B3%7D%20%20%3D%208)
To solve this do:
838.35/9315= 0.09.
This means the company charged $.09 for every kilowatt of electricity used.
Answer & Step-by-step explanation:
Since you looking for the width and you are given the length and the area, then you will divide the area by the length.
(10x² + 5x) ÷ 5x
You can also turn this into a fraction so you can know what you are dividing.
So, your width is 2x + 1
81.4% ≅ 81%. The probability that a customer ordered a hot drink given that he or she ordered a large is 81%.
The key to solve this problem is using the conditional probablity equation P(A|B) = P(A∩B)/P(B). Conditional probability is the probability of one event occurring with some relationship to one or more other events.
Similarly to the previous exercise, P(A∩B) is the probability that a customer order a large hot drink. So, P(A∩B) = 22/100 = 0.22
For P(B), is the probability that a customer order a large drink whether hot or cold. P(B) = 27/100 = 0.27
P(A|B) = 0.22/0.27 = 0.814
multiplying by 100%, we obtain 81.4%
Well knowing that the terminal arm of the standard position angle is in quadrant 2, we can determine the reference angle, in quadrant 2, by simply taking the difference between 180 and whatever the angle is.
So ø reference = 180 - ø in standard position.
Regardless, the reference angle is in quadrant 2, we need to then label the sides of the reference triangle based on the opposite and hypotenuse.
Solve for adjacent side using Pythagoras theorem.
A^2 = C^2 - B^2
A^2 = 3^2 - 2^2
A^2 = 9 - 4
A^2 =5
A = sq root of 5.
Then write the cos ratio using the new side.
Cos ø =✔️5/3. Place a negative in front of cos ø as cos is negative in second quadrant.
