Evaluate the expression when x=3, y= -4, and z= -6 xy _ z
1 answer:
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Answer:
0.5372
Step-by-step explanation:
Given that the number of births that occur in a hospital can be assumed to have a Poisson distribution with parameter = the average birth rate of 1.8 births per hour.
Let X be the no of births in the hospital per hour
X is Poisson
with mean = 1.8
the probability of observing at least two births in a given hour at the hospital
=
the probability of observing at least two births in a given hour at the hospital = 0.5372
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