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3 years ago

The square root of 5 is between which two integers? Explain your reasoning.

2 answers:

7 0

Without using a calculator, you can reason that since 2²=4 and 3²=9, since 5 is between 4 and 9, its square root must be between 2 and 3.

ryzh [129]3 years ago

6 0

Answer:

between 2 and 3

Step-by-step explanation:

find a square number that is less then 5 and a square number that is larger than 5 so that we easily their square root

These two numbers are 4 and 9 and their square roots are 2 and 3. 5 is between 4 and 9 therefore square root of 5 must be between 2 and 3

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2 years ago

John has to pay $7.00 admission for the skating rink and $1.50 per hour rollerblades. how many hours can he skate for $19. can y

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2 years ago

48 feet = how many yards

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2 years ago

What is the value of 7x2−6x when x = 4

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2 years ago

R (-3,1) and S (-1,3) are points on a circle. If RS is a diameter, find the equation of the circle.

ELEN [110]

Answer:

$\sf (x+2)^2+(y-2)^2=2$

Step-by-step explanation:

If RS is the diameter of the circle, then the midpoint of RS will be the center of the circle.

$\sf midpoint=\left(\dfrac{x_s-x_r}{2}+x_r,\dfrac{y_s-y_r}{2}+y_r \right)$

$\sf =\left(\dfrac{-1-(-3)}{2}+(-3),\dfrac{3-1}{2}+1 \right)$

$\sf =(-2, 2)$

Equation of a circle: $\sf (x-h)^2+(y-k)^2=r^2$

(where (h, k) is the center and r is the radius)

Substituting found center (-2, 2) into the equation of a circle:

$\sf \implies (x-(-2))^2+(y-2)^2=r^2$

$\sf \implies (x+2)^2+(y-2)^2=r^2$

To find $\sf r^2$ , simply substitute one of the points into the equation and solve:

$\sf \implies (-3+2)^2+(1-2)^2=r^2$

$\sf \implies 1+1=r^2$

$\sf \implies r^2=2$

Therefore, the equation of the circle is:

$\sf (x+2)^2+(y-2)^2=2$

4 0

2 years ago