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MatroZZZ [7]
3 years ago
14

Ella says the answer to $79 ÷ 4 is $19.30. What did she do wrong?

Mathematics
1 answer:
Mamont248 [21]3 years ago
4 0

Answer:

19.75

Step-by-step explanation:

while she divided the remainder 3 (then you bring down the 0) she accidentaly put 30 in 19.30 so thats why

while the correct way is to keep going with the equation until you have no remainder

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What is the midpoint of a segment (-2,-7) and (7,4)
Rasek [7]

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-7})\qquad
(\stackrel{x_2}{7}~,~\stackrel{y_2}{4})
\qquad
\left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{7-2}{2}~~,~~\cfrac{4-7}{2} \right)\implies \left(\cfrac{5}{2}~,~\cfrac{-3}{2} \right)\implies \left( 2\frac{1}{2}~,~-1\frac{1}{2} \right)

5 0
3 years ago
In a horse race with 5 horses, you make a bet by predicting the ranking of all 5 horses. Suppose you place your bet at random. W
lapo4ka [179]

Answer:

P( top two horses are predicted incorrectly in incorrect order)

= \frac{1}{2}

Step-by-step explanation:

In the horse race the outcome can be predicted in 5! = 120 ways.

Now suppose the top two horses were predicted incorrectly in incorrect order. Now, the  top horse can be predicted incorrectly in 4 ways.

Suppose the top horse was predicted to be in k-th position where k = 2, 3 ,4,5

so the second horse can be predicted to be in place from 1 to (k - 1)

So, the top two horses can be predicted  incorrectly in incorrect order

in \sum_{k =2}^{5}(k - 1) = 10 ways  

and for each prediction of the two the remaining horses may be predicted in 3! = 6 ways.

Hence ,

P( top two horses are predicted incorrectly in incorrect order)

= \frac{6 \times 10}{120}

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8 0
3 years ago
Indicate in standard form the equation of the line passing through the given points.
lorasvet [3.4K]

Answer:

y = 6

Step-by-step explanation:

Let the y-intercept form of the equation of the line is,

y = mx + b

Here, m = Slope of the line

b = y-intercept

Slope of the line passing through two points (x_1,y_1) and (x_2,y_2) is given by,

m = \frac{y_2-y_1}{x_2-x_1}

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m = \frac{6-6}{0-5}

m = 0

Equation of the line with m = 0 will be,

y = 0 + b

y = b

Since, line passes through (0, 6),

By substituting the values in the equation,

b = 6

Therefore, standard equation of the line passing through (0, 6) and (5, 6) will be,

y = 6

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Answer:

Step-by-step explanation:

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