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Elena L [17]
3 years ago
15

I need help ASAP help me answer questions and then I put a picture up

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
5 0

Answer:

(-4,9)

Step-by-step explanation:

To solve the system of equations, you want to be able to cancel out one of the variables. In this case, it'd be easiest to cancel out the x variables. To do this, you'll want to multiply everything in the first equation by 2 (2(x-5y=-49)=2x-10y=-98). Then, you can add the two equations together. 2x and -2x will cancel out, so you'll be left with -11y=-99. Next, solve for x by dividing both sides of the equation by -11, which will give you y=9. This is your y-coordinate! At this point, you're halfway to the answer as you just need your x-coordinate. It's not too difficult to find the x-coordinate, since you just substitute 9 into one of the equations. It doesn't matter which one you choose as you should get the same answer with both. I usually substitute the y-value into both equations, though, just to make sure I'm correct. Once you put the y-value into the equations, you should get x=-4 after solving it. :)

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Use the multiplication property of exponents to determine if each statement is true or false.
lisabon 2012 [21]
1)
LHS:
{a}^{4}  \times  {a}^{3}  \times a \\  =  {a}^{4 + 3 + 1}  \\  =  {a}^{7}
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2)
LHS:
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{x}^{6}  \times  {x}^{0}  \times  {x}^{2}  \times  {x}^{3}  \\  =  {x}^{6 + 0 + 2 + 3}  \\  =  {x}^{11}
LHS = RHS. So, the statement is true.

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Answer:

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Step-by-step explanation:

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