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dedylja [7]
3 years ago
11

As you walk on the beach, every detail of the rocks, shells, and sand beneath your feet seem crisp and distinct. as you look fur

ther down the beach, however, the details of the ground in the distance seem fuzzy and blurred. because of the depth perception cue of _____, you perceive the ground beneath your feet to be much closer than the ground that extends into the distance.
Physics
2 answers:
Luden [163]3 years ago
7 0
The answer that will fill in the blank is the texture gradient. This describes the things seen far from where you are standing, in which it points its different in size and the way how they look denser. It enables the person to give a sense of depth perception because of how the person sees in which it depends on how far or how the person sees it.
Kobotan [32]3 years ago
7 0

Answer:

Group of choices:

A) psychokinesis

B) texture gradient

C) convergence

D) linear perspective

The correct answer is B) Texture Gradient .

Explanation:

This is a situation that is explicitly detailed within the psychology of perception, within the theory of realistic perception. The texture gradient is a depth condition that is determined when there is a change in the size of the objects that are on a surface and the density that they represent compared to the distance that the observer is.

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Why do black holes have a large gravitational pull that even light cannot escape from
Annette [7]

Answer:

Because matter has been squeezed into a tiny space.

Explanation:

According to NASA, this can happen when a star is dying.

8 0
3 years ago
Read 2 more answers
A 60 cm diameter wheel accelerates from rest at a rate of 7 rad/s2. After the wheel has undergone 14 rotations, what is the radi
Mamont248 [21]

Answer:

a=368.97\ m/s^2

Explanation:

Given that,

Initial angular velocity, \omega=0

Acceleration of the wheel, \alpha =7\ rad/s^2

Rotation, \theta=14\ rotation=14\times 2\pi =87.96\ rad

Let t is the time. Using second equation of kinematics can be calculated using time.

\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\\t=\sqrt{\dfrac{2\theta}{\alpha }} \\\\t=\sqrt{\dfrac{2\times 87.96}{7}} \\\\t=5.01\ s

Let \omega_f is the final angular velocity and a is the radial component of acceleration.

\omega_f=\omega_i+\alpha t\\\\\omega_f=0+7\times 5.01\\\\\omega_f=35.07\ rad/s

Radial component of acceleration,

a=\omega_f^2r\\\\a=(35.07)^2\times 0.3\\\\a=368.97\ m/s^2

So, the required acceleration on the edge of the wheel is 368.97\ m/s^2.

6 0
3 years ago
According to the law of conservation of energy, how will the sum of the kinetic
Margaret [11]

Answer:

I think that this ans may help you

3 0
3 years ago
The velocity of a 640-kg auto is changed from 10.0 m/s to 44.0 m/s in 71.0 s by an external, constant force. (a) What is the res
n200080 [17]

Answer:

(a) <em>change in momentum of the car = 21760 kgm/s</em>

(b) <em>The magnitude of the force = 306.48 N</em>

Explanation:

<em>(a)</em>

<em>Change in momentum: </em><em>This is the product of mass and change in velocity. The unit of momentum is kgm/s. It can be expressed mathematically as,</em>

Change in momentum of the car = m(v-u)................. Equation 1

Where m = mass of the car, v = final velocity of the car, u = initial velocity of the car.

<em>Given: m = 640 kg, v = 44.0 m/s, u = 10.0 m/s.</em>

<em>Substituting these values into equation 1,</em>

<em>Change in momentum of the car = 640 (44-10)</em>

<em>change in momentum of the car = 640× 34</em>

<em>change in momentum of the car = 21760 kgm/s</em>

<em>change in momentum of the car = 21760 kgm/s</em>

<em>(b) Force:</em><em> Force of a body can be defined as the product of mass and its acceleration. It is measured in Newton (N). It can be expressed mathematically as,</em>

<em>Force = ma ................................ Equation 2</em>

<em> </em><em>    Or</em>

<em>Force = m(v-u)/t...................................... Equation 3</em>

<em>Where m = mass of the car, v = final velocity of the car, u = initial velocity of the car, a = acceleration of the car, t = time taken to change the velocity.</em>

<em>Given: m = 640 kg, u = 10.0 m/s v = 44 m/s, t = 71 s.</em>

<em>Substituting these values into equation 3</em>

<em>Force = 640(44-10)/71</em>

<em>Force = (640×34)/71</em>

<em>Force = 306.48 N</em>

<em>The magnitude of the force = 306.48 N</em>

3 0
3 years ago
Hiii please help i’ll give brainliest if you give a correct answer please thanks!
lakkis [162]

Answer: the first one

Explanation: good luck!

8 0
3 years ago
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