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sveta [45]
3 years ago
13

Which of the following is the correct graph of the compound inequality 4p + 1 > −15 or 6p + 3 < 45?

Mathematics
2 answers:
astraxan [27]3 years ago
6 0

Answer:

4p + 1 > −15 or 6p + 3 < 45

has solution any number.

The graph looks like this

<~~~~~~~~~~~~~~~~~~~~~~~~~~~>

     ---------(-4)---------(7)-------------

The shading is everywhere from left to right.

Step-by-step explanation:

Let's solve this first:

4p+1>-15

Subtract 1 on both sides:

4p>-16

Divide both sides by 4:

p>-4

or

6p+3<45

Subtract 3 on both sides:

6p<42

Divide both sides by 6:

p<7

So our solution is p>-4 or p<7

So let's graph that

~~~~~~~~~~~~~~~~~~~~~~~~~~~~O

                         O~~~~~~~~~~~~~~~~~~~~~~~~~~~~ p>-4

---------------------(-4)---------------------(7)--------------------

or is a key word! or means wherever the shading exist for either is a solution.

So this shading is everywhere.

The answer is all real numbers.

The final graph looks like this:

<~~~~~~~~~~~~~~~~~~~~~~~~~~~>

     ---------(-4)---------(7)-------------

The shading is everywhere from left to right.

ValentinkaMS [17]3 years ago
5 0

Answer:

Solution is (-∞,∞)

Step-by-step explanation:

4p + 1 > -15 \ or \ 6p + 3 < 45

Solve each inequality separately

4p + 1 > -15

Subtract 1 from both sides

4p> -16

Divide both sides by 4

p> -4

Solve the second inequality

6p + 3 < 45

Subtract 3 from both sides

6p< 42

Divide both sides by 6

p< 7

p> -4 \ or \p< 7

Solution is (-∞,∞)

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antiseptic1488 [7]

Answer:

m=12

Explanation:

Given any quadratic function, y=ax²+bx+c.

We can determine the nature of the roots of such quadratic function by examining the discriminant, D where:

D=b^2-4ac

• If D>0, the roots are real and unequal.

,

• If D=0, the roots are real and equal.

,

• If D<0, the roots are complex.

In our given equation:

\begin{gathered} y=18x^2+mx+2 \\ a=18,b=m,c=2 \end{gathered}

For the function to have exactly one zero, the value of D=0.

\begin{gathered} D=b^2-4ac=m^2-4(18)(2)=m^2-144 \\ D=0\implies m^2-144=0 \\ Add\text{ 144 to both sides.} \\ m^2=144 \\ Take\text{ the square root of both sides} \\ \sqrt{m^2}=\sqrt{144} \\ m=12 \end{gathered}

The value of m for which the function will have one zero is 12.

4 0
1 year ago
Sub :- Linear Equations
vesna_86 [32]

Hiiiiiiiiiiiii

The value of x is 1 & y is 2 (a).

Steps are attached.

______

꧁✿ ᴿᴬᴵᴺᴮᴼᵂˢᴬᴸᵀ2222 ✬꧂

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2 years ago
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