Answer:
product A on machine 1 would make 27 units (rounded down) 81 dollars profit.
product A on machine 2 would make 25 units (rounded down) 75 dollars profit.
product b on machine 1 would make 15 units (rounded down) 75 dollars profit.
product b on machine 2 would make 16 units (rounded down) 80 dollars profit.
Step-by-step explanation:
a1 refers to product a on machine 1
a2 refers to product a on machine 2
same rule applies for product b 1 and 2
Answer:
The length of the third side is ( x - 2 )
Step-by-step explanation:
Volume of a box is the product of its length, width and height.
Volume of box = length × width × height.
One side is (x - 4) and another side is (2x + 1).
These given sides can be either length, height or width.
The volume of a box is given by V = 2x3-11x2 +10x +8. This means each of the sides are factors of the volume. To get the third side, we divide the volume by the product of the two given sides.
Product of the two given sides =
( x-4 ) (2x + 1) = 2x^2 + x - 8x + 4
= 2x^2 - 7x - 4
The long division is shown on the attached photo
The length of the third side is ( x - 2 )
<span>The best answer is:
If it is a rectangle, then it does not have three sides.
</span>This statement is also known as the equivalent contra-positive.
Answer:
6000 in³
Step-by-step explanation:
To solve this problem, we simply have to find the volume of the shipping container that will be just enough to contain the 20 soda boxes.
To do this, we find the volume of each soda box and multiply it by the total number of soda boxes held by the shipping container.
Volume of the box = L * B * H
L = length = 15 in
B = breadth = 4 in
H = height = 5 in
V = 15 * 4 * 5 = 300 in³
This is the volume of each soda box.
The volume of 20 soda boxes will then be:
V = 20 * 300 = 6000 in³
This is the volume of 20 soda boxes and hence, the minimum size the shipping container can be.
