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3 years ago

The number 512 is a perfect cube because 512 = 83.

Mathematics

2 answers:

sleet_krkn [62]3 years ago

7 0

The answer to your question is 125 hope this helps !

alexgriva [62]3 years ago

3 0

Step-by-step explanation:

the number which is a perfect cube :

125, because 125 = 5³

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Layla is saving up money for a trip. She already has $650 saved and plans to save an additional $150 each month for the trip.

dimulka [17.4K]

S=150m+650
650 is how much she already saved
150 is how much per month

8 0

4 years ago

Solve for x 2.3(6-x)+22=96-2.3(2x+12)

melomori [17]

Hello!

(this took me 20 minutes to type out from what I wrote on paper lol)

I'm going to guide you through this one step at a time

Step 1: Simplify both sides of the equation.

2.3(6−x)+22 = 96−2.3(2x+12)

(2.3)(6)+(2.3)(−x)+22 = 96+(−2.3)(2x)+(−2.3)(12) (use distributive property of multiplication)

13.8+−2.3x+22 = 96+−4.6x+−27.6

(−2.3x)+(13.8+22) = (−4.6x)+(96+−27.6) (Combine The Like Terms)

−2.3x+35.8 = −4.6x+68.4

Step 2: now, add 4.6x to both sides.

−2.3x+35.8+4.6x = −4.6x+68.4+4.6x

2.3x+35.8 = 68.4

Step 3: next, subtract 35.8 from both sides.

2.3x+35.8−35.8 = 68.4−35.8

2.3x = 32.6

Step 4: Divide both sides by 2.3.

$\frac{2.3X}{2.3}$ = $\frac{32.6}{2.3}$

fractions solved: x = 14.173913

your final answer is: x = 14.173913

I hope this helps, and have a nice day!

5 0

3 years ago

Descent, Inc., produces a variety of climbing and mountaineering equipment. One of its products is a traditional three-strand cl

Rainbow [258]

Solution :

Assuming $\sigma_1^2=\sigma_2^2$

We have to test

$H_0:\mu_1=\mu_2$

Against $H_a: \mu_1 \neq \mu_2$

Level of significance, $\alpha = 0.05$

$s_p=\sqrt{\frac{(n_1-1)s_1^2+ (n_2-1)s_2^2}{n_1+n_2-2}}$

$s_p=\sqrt{\frac{(25-1)(425)^2+ (20-1)(415)^2}{25+20-2}}$

= 420.6107

Under $H_0$ , the t-statistics is as follows:

$t=\frac{(\overline{x_1} - \overline{x_2})}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}} \sim$ $\text{t with }(n_1+n_2-2) \ DF$

$t=\frac{(7200-7087)}{(420.6107)\sqrt{\frac{1}{25}+\frac{1}{20}}}$

= 0.90

DF = (25 + 20 - 2)

= 43

P-value of the test = 0.375

Since the p value is more than 0.05, we fail to reject our null hypothesis.

There is no difference between then mean tensile strength of the ropes that is produced in the Bozeman and Challis.

3 0

3 years ago

What is 1/3 divided by 1/9

vodka [1.7K]

Answer:

Step-by-step explanation:

1/3 / 1/9 =

1/3 x 9 =

6 0

4 years ago

Read 2 more answers

In the past, the population proportion of consumers preferring orange juice with no pulp was equation. To test if this populatio

geniusboy [140]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

a) For the null hypothesis,

P = 0.45

For the alternative hypothesis,

P ≠ 0.45

b) For the decision rule, we would reject H0 if 0.1 > p value and accepth H0 if 0.1 < p value

Considering the population proportion, probability of success, p = 0.45

q = probability of failure = 1 - p

q = 1 - 0.45 = 0.55

Considering the sample,

Sample proportion, p = x/n

Where

x = number of success = 52

n = number of samples = 120

p = 52/120 = 0.43

c) We would determine the test statistic which is the z score

z = (p - P)/√pq/n

z = (0.43 - 0.45)/√(0.45 × 0.55)/120 = - 0.44

Recall, population proportion, P = 0.45

The difference between sample proportion and population proportion(P - p) is 0.45 - 0.43 = 0.02

Since the curve is symmetrical and it is a two tailed test, the p for the left tail is 0.45 - 0.02 = 0.43

the p for the right tail is 0.45 + 0.02 = 0.47

These proportions are lower and higher than the null proportion. Thus, they are evidence in favour of the alternative hypothesis. We will look at the area in both tails. Since it is showing in one tail only, we would double the area

From the normal distribution table, the area below the test z score in the left tail 0.3336

We would double this area to include the area in the right tail of z = 0.44 Thus

p = 0.3336 × 2 = 0.67

d) Since alpha, 0.1 < than the p value, 0.67, then we would fail to reject the null hypothesis. Therefore, at a 1% level of significance, we do not have enough evidence to reject the null hypothesis

4 0

3 years ago