Answer with Step-by-step explanation:
Since 1 mole of sand will contain Avagadro's Number of sand particles (by definition of 1 mole)
Thus we have
1 mole of sand =
sand particles
Thus in number of trillion sand particles we have no of trillion sand particles in 12 mole is
![\frac{6.022\times 10^{23}}{10^{12}}=6.022\times 10^{11}](https://tex.z-dn.net/?f=%5Cfrac%7B6.022%5Ctimes%2010%5E%7B23%7D%7D%7B10%5E%7B12%7D%7D%3D6.022%5Ctimes%2010%5E%7B11%7D)
Now since it is given that mass of 1 trillion sand particles is 1000 tonnes Thus the mass of
trillion sand particles is
![Mass=1000\times 6.022\times 10^{11}=6.022\times 10^{14}tonnes](https://tex.z-dn.net/?f=Mass%3D1000%5Ctimes%206.022%5Ctimes%2010%5E%7B11%7D%3D6.022%5Ctimes%2010%5E%7B14%7Dtonnes)
Part 2)
Since it is given that volume of 1 sand particle is
thus the volume of 1 mole of sand is volume of
sand particles
Thus volume of 1 mole is ![V=1.00\times 10^{-18}km^{3}\times 6.022\times 10^{23}=6.022\times 10^{5}km^{3}](https://tex.z-dn.net/?f=V%3D1.00%5Ctimes%2010%5E%7B-18%7Dkm%5E%7B3%7D%5Ctimes%206.022%5Ctimes%2010%5E%7B23%7D%3D6.022%5Ctimes%2010%5E%7B5%7Dkm%5E%7B3%7D)
Now since the Area of united states is ![A=3.6\times 10^{6}mile^{2}=5.8\times 10^{6}km^{2}](https://tex.z-dn.net/?f=A%3D3.6%5Ctimes%2010%5E%7B6%7Dmile%5E%7B2%7D%3D5.8%5Ctimes%2010%5E%7B6%7Dkm%5E%7B2%7D)
Thus the depth of the sand pile is
![Depth=\frac{Volume}{Area}=\frac{6.022\times 10^5}{5.8\times 10^6}=0.10387km=103.8meters](https://tex.z-dn.net/?f=Depth%3D%5Cfrac%7BVolume%7D%7BArea%7D%3D%5Cfrac%7B6.022%5Ctimes%2010%5E5%7D%7B5.8%5Ctimes%2010%5E6%7D%3D0.10387km%3D103.8meters)
Answer:
2300
Step-by-step explanation:
Add the two numbers in the middle and divide br 2.
Call the point of attachment at the top of the building point T. (Angle T = 25°) The angle N = 180° -32° -25° = 123°. The Law of Sines tells you the relationship ...
... TM/sin(N) = MN/sin(T)
... MN = TM·sin(T)/sin(N) = (200 ft)·sin(25°)/sin(123°)
... MN ≈ 100.8 ft
Answer:
B
Step-by-step explanation:
Think: If we go from A to B, x decreases by 6, from 2 to -4. One third of that distance is 2. So, the x-coordinate of the point that divides line segment AB in the ratio 1:2 as we go from A to B is 2-2=0.
As we go from A to B, y increases by 9-(-3) =12.
One third of that is 4. So, y increases from -3 to +1.
The point in question is (0,1).