Answer:
1.16
Step-by-step explanation:
Given that;
For some positive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770.
This implies that:
P(0<Z<z) = 0.3770
P(Z < z)-P(Z < 0) = 0.3770
P(Z < z) = 0.3770 + P(Z < 0)
From the standard normal tables , P(Z < 0) =0.5
P(Z < z) = 0.3770 + 0.5
P(Z < z) = 0.877
SO to determine the value of z for which it is equal to 0.877, we look at the
table of standard normal distribution and locate the probability value of 0.8770. we advance to the left until the first column is reached, we see that the value was 1.1. similarly, we did the same in the upward direction until the top row is reached, the value was 0.06. The intersection of the row and column values gives the area to the two tail of z. (i.e 1.1 + 0.06 =1.16)
therefore, P(Z ≤ 1.16 ) = 0.877
Answer:
Question 2 the answer is C) y = -3/2x + 2
Question 3 the answer is D) x = 4
Step-by-step explanation:
To solve either we first need to know that parallel lines have the same slope.
So in #2 we know that the new line will also have a slope of -3/2. Therefore, we can use that along with the point given in the problem in point-slope form to get the new equation.
y - y1 = m(x - x1)
y + 1 = -3/2(x - 2)
y + 1 = -3/2x + 3
y = -3/2x + 2
And for #3, we know that we have a vertical line due to the fact that it is expressed as x = a number. Therefore, we must have the same in the answer. D is the only one that has such an answer.
Answer:
Step-by-step explanation:
9514 1404 393
Answer:
(x, y) = (-2, -1) or (2, 1)
Step-by-step explanation:
Substitute for x in the first equation:
(2y)^2 +3(2y)y = 10
10y^2 = 10
y^2 = 1
y = ±1
x = 2y = ±2
Solutions are (x, y) = (-2, -1) or (2, 1).
I would think it’s a square
