3 years ago

Does (2,-6 )satisfy the equation y= -3x

Mathematics

2 answers:

maksim [4K]3 years ago

6 0

Answer:

Yes

Step-by-step explanation:

Step 1: Plug in

-6 = -3(2)

-6 = -6

Answer: Yes

MatroZZZ [7]3 years ago

5 0

Answer:

Yes!

Step-by-step explanation:

(2,-6) x=2 y=-6

so, y=-3x would end up as -6=-3(2)

-3 x 2 = -6 so it satisfies the equation

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A rectangle has a diagonal 15 cm and one side 8 cm finde the perimeter p of the rectangle

snow_lady [41]

Consider the right angles triangle with hypotenuse 15 and leg 8 cm formed by drawing the diagonal.

The other leg (x) will be the other side of the rectangle and , by Pythagoras we have:-

15^2 = 8^2 + x^2

x^2 = 225 - 64

x^2 = 161

x = 12.69 cms

So the perimeter p = 2*8 + 2* 12.69

= 16 + 25.38

= 41.38 cms (answer)

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A,C,and D.

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Step-by-step explanation:

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Amiraneli [1.4K]

Answer:

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3 years ago

Is domain of f(x,y) = 1 + (4 -y^2)^1/2 open, closed or neither is it bounded or unbounded?

omeli [17]

Answer:

Closed and Bounded.

Step-by-step explanation:

Hi there!

1) Let's start by finding the values in which the function is defined. Remember that this can be rewritten:

$f(x,y) = 1 + (4 -y^2)^{\frac{1}{2}} \:id\:est\:f(x,y)=1+\sqrt{(4 -y^2)}$

Since every quadratic root are defined for values $\geq$ 0 then, this help us to understand that we need calculate what interval this Domain is:

$4-y^{2} \geq 0\\4-y^{2}-4\geq -4\\-y^{2}\geq-4 \\y^{2}\leq4\\-2\leq y\leq 2$

$D=[-2,2]$

2) Graphically speaking, the domain is closed. For the values -2 and 2 are included, and bounded.

Bounded functions have all of their points contained by some circle origin centered. Check it out below.

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4 years ago