Let

be a probability that i-th light fails, where i=1,2,3. Then,

is the probability that i-th light remain bright.
<span>If the lights fail independently of each other, the probability that a string of lights will remain bright for two years is:
</span>

.
-16-1x = -4x +8
add 1x to each side
-16 = -3x +8
subtract 8 from each side
-24 = -3x
divide both sides by -3
x = -24 / -3 = 8
x = 8
Answer:
a=4, b = -2
Step-by-step explanation:
Use elimination: subtract two equations. you get -6b = 12, so b = -2. Substitute this into the first equation and get a -8 = -4, so a = 4
Set up a proportionality and simplify the fraction...hope this helps :)
1. When ever the denominator have the power is negative then flip it to numerator so
3x6/9 simplified equal x6/3
2. 6/5k^10 w^3