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Juliette [100K]
3 years ago
9

Esther ate seven less than six times as many jelly beans as Jake. Esther ate 77 jelly beans. How many jelly beans did Jake eat?

Mathematics
2 answers:
anygoal [31]3 years ago
4 0
462 should be correct sorry if not
Ostrovityanka [42]3 years ago
4 0

Answer:

My best answer is 5 because it says that Esther ate more than Jake, and 77 divided by 6 is 12.83. Subtract this by 7 and you get 5.83.

Hope this helps ^-^

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Find exact values for sin θ and cos θ if tan θ = -√3 and θ terminates in Quadrant II.
vivado [14]
Hello : 
<span>tan θ = -√3
sin</span>θ = √3/2    1/2                      
cosθ = -1/2   

5 0
3 years ago
7th grade Ms. Takemoto wants to raise her math grade to a 95 to improve her chances of winning a math scholarship. Her math aver
malfutka [58]
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8 0
3 years ago
Indicate the equation of the given line in standard form.
Lorico [155]
We have that
<span>triangle ABC
where
A(-5, 5), B(1, 1), and C(3, 4) are the vertices

using a graph tool
see the attached figure

the hypotenuse is the segment AC

find the equation of the line AC
</span>A(-5, 5) C(3, 4) 
<span>
step 1
find the slope m
m=(y2-y1)/(x2-x1)-----> m=</span>(4-5)/(3+5)-----> m=-1/8

step 2
with C(3,4) and m=-1/8
find the equation of a line
y-y1=m*(x-x1)-----> y-4=(-1/8)*(x-3)----> y=(-1/8)*x+(3/8)+4
y=(-1/8)*x+(3/8)+4----> multiply by 8----> 8y=-x+3+32
8y=-x+35
the standard form is Ax+By=C
so
x+8y=35
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the answer is
x+8y=35


7 0
3 years ago
Find the height of the building to the nearest foot in the diagram below. Show work.
stira [4]

Answer:

height : 150 feet

Step-by-step explanation:

\sf \sf tan(x)= \dfrac{opposite}{adjacent}

using tan rule:

\hookrightarrow \sf tan(62)= \dfrac{b}{80}

\hookrightarrow \sf b = tan(62)*80

\hookrightarrow \sf b =150.46 \ feet

5 0
2 years ago
Read 2 more answers
Set up a double integral for calculating the flux of the vector field ????⃗ (????⃗ )=????⃗ , where ????⃗ =⟨x,y,z⟩, through the p
Tema [17]

Answer:

-937.5π

Step-by-step explanation:

F (r) = r = (x, y, z) the surface equation z = 3(x^2 + y^2) z_x = 6x, z_y = 6y the normal vector n = (- z_x, - z_y, 1) = (- 6x, - 6y, 1)

Thus, flux ∫∫s F · dS is given as;

∫∫ <x, y, z> · <-z_x, -z_y, 1> dA

=∫∫ <x, y, 3x² + 3y²> · <-6x, -6y, 1>dA , since z = 3x² + 3y²

Thus, flux is;

= ∫∫ -3(x² + y²) dA.

Since the region of integration is bounded by x² + y² = 25, let's convert to polar coordinates as follows:

∫(θ = 0 to 2π) ∫(r = 0 to 5) -3r² (r·dr·dθ)

= 2π ∫(r = 0 to 5) -3r³ dr

= -(6/4)πr^4 {for r = 0 to 5}

= -(6/4)5⁴π - (6/4)0⁴π

= -937.5π

4 0
4 years ago
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