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NeTakaya
2 years ago
10

Solve the equation. –4n + 7 + 2n = 1 A. 1 B. 3 C. –3 D. 4

Mathematics
2 answers:
Kisachek [45]2 years ago
8 0
-2n=-6. n=3. So, b.3.
kicyunya [14]2 years ago
3 0
B 3 the answer is b
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Help pls and thank you
netineya [11]
A, C, and D are all correct answers, since you are taking away 4 in each of the answers. Hope this helped!
6 0
3 years ago
Solve the inequality if possible 4(3-2x)>2(6-4x)
GenaCL600 [577]

Final Answer: No Solution

Steps/Reasons/Explanation:

Question: 4(3-  2x) > 2(6-  4x)

<u>Step 1</u>: Divide both sides by 2.

2(3 - 2x) > 6 - 4x

<u>Step 2</u>: Expand.

6 - 4x > 6 - 4x

<u>Step 3</u>: Since 6 - 4x > 6 - 4x is false, we have no solution.

No Solution

~I hope I helped you :)~

6 0
2 years ago
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3 years ago
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mina [271]
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Tems11 [23]

ince the problem is only asking for 4 years, we can just calculated it out year by year. Recall the formula for compounding interest: A = P(1+r)n, where A is the total amount, P is the principle (amount you start with), r is the interest rate per period of time, and n is the number of periods (in this case, r is annual interest rate, so n is number of years). At the beginning (Year 0), Lou starts off with 10000: A = 10000 At the end of Year 1, Lou earned interest on that amount, plus he has deposited another 5000: A = 10000(1.08) + 5000 End of Year 2, Lou's interest from the year 0 amount has compounded, he has started earning interest on the amount deposited last year, and he deposits another 5000: A = 10000(1.08)2 + 5000(1.08) + 5000 End of Year 3, same idea. Lou has earned compounding interest on all existing deposits, and deposits another 5000: A = 10000(1.08)3 + 5000(1.08)2 + 5000(1.08) + 5000 End of Year 4, same idea: A = 10000(1.08)4 + 5000(1.08)3 + 5000(1.08)2 + 5000(1.08) + 5000 = 36135.45



7 0
2 years ago
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