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2 years ago

Use the combination formula to solve a problem when n = 7 and r = 5.

Mathematics

2 answers:

sdas [7]2 years ago

8 0

I might be wrong but I think it’s b sorry if wrong :)

tamaranim1 [39]2 years ago

3 0

THE ANSWER IS MOST LIKELY B.42

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a regular pentagon-based pyramid has 5 faces which are equilateral triangles the perimeter of it's net is 70cm what is the perim

netineya [11]

Answer:

35cm

Step-by-step explanation:

The net of a regular pentagon has 10 sides.

Since each of the faces are equilateral triangles, the side lengths are equal.

Therefore:

Length of each side of the net = 70/10 =7cm

Therefore, the base is a regular pentagon of side length 7cm.

The perimeter of the base of the pyramid = 5 X 7

=35cm

The perimeter of the base of the pyramid is 35cm.

3 0

3 years ago

Last year there were k pies baked in the bake sale. This year, there were 187 pies baked. Using k, write an expression of the to

Shkiper50 [21]

Answer:

Step-by-step explanation:

4 0

3 years ago

A recipe for individual chocolate hazelnut tarts calls for ½ cup of hazelnuts per tart. If 1 cup of hazelnuts weighs 4 ounces, w

DerKrebs [107]

Answer:

The amount is sufficient to make 75 tarts.

Step-by-step explanation:

We have been given that a recipe for individual chocolate hazelnut tarts calls for ½ cup of hazelnuts per tart and 1 cup of hazelnuts weighs 4 ounces.

The half cup of hazelnuts will weigh 2 ounces $(\frac{4}{2}=2)$ .

1 kg equals 35.274 ounces.

$\text{5 kg}=5\times 35.274\text{ ounces}$

$\text{5 kg}=176.37\text{ ounces}$

Since each tart needs ½ cup of hazelnuts and half cup of hazelnuts will weigh 2 ounces, so we will divide 176.37 ounces by 2 to find number of tarts.

$\frac{176.37}{2}=88.185\approx 88$

Since we can make 88 tarts from 5 kg hazelnuts, therefore, the 5-kilogram bag of hazelnuts be sufficient to make 75 tarts.

7 0

3 years ago

A person standing at the edge of a cliff throws a rock upward from a height of 180ft above ground level with an initial velocity

taurus [48]

Answer: 8.73 ft/s

Step-by-step explanation:

We have the following equation that models the motion of the rock:

$h(t)=-16t^{2}+64t+180$

Where $h(t)$ is the height of the rock at a time $t$ .

Now, if $h(t)=48 ft$ we can find $t$ and then the velocity of the rock at that height:

$48=-16t^{2}+64t+180$

Rearranging the equation:

$-16t^{2}+64t+132=0$

Multiplying the equation by -1:

$16t^{2}-64t-132=0$

Solving with the quadratic formula $t=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$ , where $a=16$ , $b=-64$ , $c=-132$ .

$t=\frac{-(-64)\pm\sqrt{(-64)^{2}-4(16)(-132)}}{2(16)}$

Choosing the positive result of the equation:

$t=5.5 s$

Since velocity $V$ is defined as the traveled distance $h(t)$ in a given time $t$ , we have:

$V=\frac{h(t)}{t}$

$V=\frac{48 ft}{5.5 s}$

$V=8.727 ft/s \approx 8.73 ft/s$ This is the velocity of the rock at the height of 48 feet

7 0

2 years ago

Please help, am i right

earnstyle [38]

Answer: yea you are

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers