Question

, Hayley sold 20 tickets to the school play for a total of $225 early bird tickets were $10 and regular price tickets were $15 write and solve a system of equations that can be used to find the cost of each type of ticket

Answer 1

Answer:

15 early tickets were sold and 5 regular tickets were sold.

Step-by-step explanation:

Let x be the number of early bird tickets sold and y be the number of regular tickets sold.

Total number of tickets sold = 20

Thus, we can write the equation,

$x + y = 20$

Cost of early bird ticket = $10

Cost of regular tickets = $15

Total cost = $225

Thus, we can write the equation,

$225 = 10x + 15y$

We solve the equation by elimination method by multiplying first equation by 10 and subtracting.

$10x + 15y-(10x+10y) = 225 - 200\\5y = 25\\\Rightarrow y=5\\x + 5 = 20\\\Rightarrow x = 15$

Thus, 15 early tickets were sold and 5 regular tickets were sold.