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castortr0y [4]
3 years ago
14

Two sides of a right triangle measure 7 units and 3 units. What is the area of the square that shares a side with the third side

of the triangle?
Mathematics
1 answer:
mihalych1998 [28]3 years ago
5 0

Answer:

21

Step-by-step explanation:

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What is the equation of this line in standard form? (-4, -1) & (1/2, 3)
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bearing in mind that standard form for a linear equation means

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\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{\frac{1}{2}}~,~\stackrel{y_2}{3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{\frac{1}{2}}-\underset{x_1}{(-4)}}}\implies \cfrac{3+1}{\frac{1}{2}+4}\implies \cfrac{4}{~~\frac{9}{2}~~}\implies \cfrac{4}{1}\cdot \cfrac{2}{9}\implies \cfrac{8}{9}

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{\cfrac{8}{9}}[x-\stackrel{x_1}{(-4)}]\implies y+1=\cfrac{8}{9}(x+4) \\\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{9}}{9(y+1)=9\left( \cfrac{8}{9}(x+4) \right)}\implies 9y+9=8(x+4)\implies 9y+9=8x+32 \\\\\\ 9y=8x+23\implies -8x+9y=23\implies 8x-9y=-23

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Answer: the answer is A

Step-by-step explanation:

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Let the line segment BD be x, then sin A = x/15
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Also y^{2} =  x^{2} + (25)^{2}  \\ =  (15sinA)^{2} + 625 \\ =225 sin^{2} A+625 \\ y= \sqrt{225 sin^{2} A+625} 

The last option
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