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2 years ago

Write the equation of the line that has a slope of 3/4 and yintercept of -7

Mathematics

2 answers:

kifflom [539]2 years ago

6 0

Answer:

Step-by-step explanation:

y = mx + b

y = 3/4x - 7

Hope this helps!

vladimir2022 [97]2 years ago

3 0

Answer:

y= 3/4x -7

Step-by-step explanation:

equation of a line

y= mx+b

the slope is m

and the y intercept is b

in this case it would be

y= 3/4x -7

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The negative sign in 15t-2t belongs to the term____?

alexdok [17]

The expression 15t – 2t not equivalent to 2t – 15t because the negative sign in 15t – 2t belongs to the term 2t.

Solution:

Given expressions are 15t – 2t and 2t – 15t.

To determine 15t – 2t is equivalent to 2t – 15t or not.

Substitute t = 2 in above two expressions.

15t – 2t = 15(2) – 2(2)

= 30 – 4

= 26

2t – 15t = 2(2) – 15(2)

= 4 – 30

= –26

The values of the expressions are different when t = 2.

So, 15t – 2t is not equivalent to 2t – 15t.

Hence the expression 15t – 2t not equivalent to 2t – 15t because the negative sign in 15t – 2t belongs to the term 2t.

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3 years ago

Write the slope-intercept form of the equation of the line that is perpendicular to and passes through Point X. Show all work fo

Semmy [17]

Answer:

$y =\dfrac{12}{5}x + 22$

Step-by-step explanation:

Slope-intercept form of line:

First find the slope of the line AB. ie, m

Slope of the perpendicular line = -1/m

(2 , 3) ⇒ x₁ = 2 & y₁ = 3

(-10, 8) ⇒ x₂ = -10 & y₂ = 8

$\boxed{Slope=\dfrac{y_2-y_1}{x_2-x_1}}$

$= \dfrac{8-3}{-10-2}\\\\=\dfrac{5}{-12}\\\\=\dfrac{-5}{12}$

$\sf slope \ of \ the \ perpendicular \ line \ m_1 = \dfrac{-1}{m}= -1 \ \div \dfrac{-5}{12}$

$\sf = -1 * \dfrac{12}{-5}=\dfrac{12}{5}$

Equation of the required line: y = mx + b

$y =\dfrac{12}{5}x+b$

The line passes through (-5 , 10). Substitute in the above equaiton,

$10 =\dfrac{12}{5}*(-5) + b\\\\ 10 = (-12) + b\\\\$

10 + 12 = b

b = 22

Equation of the line:

$y =\dfrac{12}{5}x + 22$

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3 years ago