All categories

3 years ago

Which set of numbers is included in the solution set of 4-3x<-2

Mathematics

1 answer:

iren [92.7K]3 years ago

3 0

$4 - 3x < - 2 \\ - 3x < - 2 - 4 \\ - 3x < - 6 \\ - x < - 2 \\ x > 2$

The answer is A (2.5, 8, 15), since these integers are greater than 2.

Hope this helps. - M

You might be interested in

What is the additive identity of a

Lady_Fox [76]

Answer:

a+0 (or just 0)

Step-by-step explanation:

The additive identity is when you add any number by zero. This is because an additive identity is what number do you add to make the same number (since it's additive it is zero, if it were multiplicative, it'd be 1)

6 0

3 years ago

In triangle ΔABC, ∠C is a right angle and CD is the height to AB . Find the angles in ΔCBD and ΔCAD if: Chapter Reference a m∠A

Strike441 [17]

Answer:

Given A triangle ABC in which

∠C =90°,∠A=20° and CD ⊥ AB.

In Δ ABC

⇒∠A + ∠B +∠C=180° [ Angle sum property of triangle]

⇒20° + ∠B + 90°=180°

⇒∠B+110° =180°

∠B =180° -110°

∠B = 70°

In Δ B DC

∠BDC =90°,∠B =70°,∠BC D=?

∠BDC +,∠B+∠BC D=180°[ angle sum property of triangle]

90° + 70°+∠BC D =180°

∠BC D=180°- 160°

∠BC D = 20°

In Δ AC D

∠A=20°, ∠ADC=90°,∠AC D=?

∠A + ∠ADC +∠AC D=180° [angle sum property of triangle]

20°+90°+∠AC D=180°

110° +∠AC D=180°

∠AC D=180°-110°

∠AC D=70°

So solution are, ∠AC D=70°,∠ BC D=20°,∠DB C=70°

5 0

3 years ago

Find the 13th term of the arithmetic sequence -3x – 1,42 + 4,112 + 9, ...

Strike441 [17]

Answer:

The 13th term is 81x + 59.

Step-by-step explanation:

We are given the arithmetic sequence:

$\displaystle -3x -1, \, 4x +4, \, 11x + 9 \dots$

And we want to find the 13th term.

Recall that for an arithmetic sequence, each subsequent term only differ by a common difference d. In other words:

$\displaystyle \underbrace{-3x - 1}_{x_1} + d = \underbrace{4x + 4} _ {x_2}$

Find the common difference by subtracting the first term from the second:

$d = (4x+4) - (-3x - 1)$

Distribute:

$d = (4x + 4) + (3x + 1)$

Combine like terms. Hence:

$d = 7x + 5$

The common difference is (7x + 5).

To find the 13th term, we can write a direct formula. The direct formula for an arithmetic sequence has the form:

$\displaystyle x_n = a + d(n-1)$

Where a is the initial term and d is the common difference.

The initial term is (-3x - 1) and the common difference is (7x + 5). Hence:

$\displaystyle x_n = (-3x - 1) + (7x+5)(n-1)$

To find the 13th term, let n = 13. Hence:

$\displaystyle x_{13} = (-3x - 1) + (7x + 5)((13)-1)$

Simplify:

$\displaystyle \begin{aligned}x_{13} &= (-3x-1) + (7x+5)(12) \\ &= (-3x - 1) +(84x + 60) \\ &= 81x + 59 \end{aligned}$

The 13th term is 81x + 59.

3 0

3 years ago

32 and 2.56 what is the unit rate

Serggg [28]

12.5

I hope this helped.

5 0

3 years ago

HELP ASAP : Find the largest value of n such that 5x^2+nx+48 can be factored as the product of two linear factors with integer c

Anna71 [15]

Answer:

$n=241$

Step-by-step explanation:

We are given

$5x^2+nx+48$

Let's assume it can be factored as

$5x^2+nx+48=(5x-s)(x-r)$

now, we can multiply right side

and then we can compare it

$5x^2+nx+48=5x^2-5rx-sx+rs$

$5x^2+nx+48=5x^2-(5r+s)x+rs$

now, we can compare coefficients

$rs=48$

$5r+s=-n$

$n=-(5r+s)$

now, we can find all possible factors of 48

and then we can assume possible prime factors of 48

$48=-+(1\times 48)$

$48=-+(2\times 24)$

$48=-+(3\times 16)$

$48=-+(4\times 12)$

$48=-+(6\times 8)$

Since, we have to find the largest value of n

So, we will get consider larger value of r because of 5r

and because n is negative of 5r+s

so, we will both n and r as negative

So, we can assume

r=-48 and s=-1

so, we get

$n=-(5\times -48-1)$

$n=241$

7 0

3 years ago