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3 years ago

Help me please!!!!!!!

Mathematics

2 answers:

Mandarinka [93]3 years ago

7 0

Can’t really see it and that other person is a bot

Aneli [31]3 years ago

6 0

I took this one and the answer B is the correct answer

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Allie is going to select a card from the group of cards shown. Complete each statement.

dolphi86 [110]

Answer:

I don't get it is there supposed to be a pic?

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3 years ago

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Jan's age is 3 years less than twice tritt's age. The sum of their ages is 30. Find their ages.

Mashutka [201]

J + t = 30
j = 2t - 3

2t - 3 + t = 30
3t - 3 = 30
3t = 30 + 3
3t = 33
t = 33/3
t = 11 <=== tritt's age is 11

j = 2t - 3
j = 2(11) - 3
j = 22 - 3
j = 19 <== jan's age is 19

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3 years ago

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A rectangle is 6yards longer than it is wide. Find the dimensions of the rectangle if it’s area is 187 square yards

emmasim [6.3K]

Answer:

Width = 11 yards

Length = 17 yards

Step-by-step explanation:

First of all, the length of the rectangle is 6 yards longer than the width, this means, length = width + 6 yards. This dimensions can be represented on figure 1, where w is width, and l, for length.

We know the area of a rectangle is A = width x length

For our case 187 = w . (w + 6)

Using the Distributive Property for the multiplication we obtain

$187 = w^{2} +6w$

$w^{2} +6w-187 =0,$

Using the quadratic formula $w=\frac{-b\±\sqrt{b^{2}-4ac } }{2a}$ where a = 1, b = 6, c = - 187 and replacing into the formula, we will have:

$w=\frac{-6\±\sqrt{6^2-4(1)(-187)} }{2(1)}$

$w=\frac{-6\±\sqrt{36+748} }{2}=\frac{-6\±\sqrt{784} }{2}=\frac{-6\±28}{2}$

We have two options: $w=\frac{-6+28}{2}=\frac{22}{2}=11 yards$

$w=\frac{-6-28}{2}=\frac{-34}{2}=-17 yards$ But a distance (width) can not be negative so, this answer for w must be discarded.

The answer must be width = 11 yards.

To find the length $l =\frac{187}{11}=17 yards$

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3 years ago

Jackson ordered 3 miles of fencing to make a pasture for his goats. What are two other equivalent measures you can use too descr

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Add 3 and 2 together and you will get 5 that's the answer

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3 years ago

Joe says that x

irga5000 [103]

The equations x+5x=16
and x+5x+25=16
No, the equations are not equal. In order for an equation to be equal the equation x+5x=16 contains 25 less than the second equation.

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3 years ago