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vichka [17]
3 years ago
11

Which statement correctly compares the function shown on this graph with

Mathematics
2 answers:
UkoKoshka [18]3 years ago
7 0

Answer: I think it’s A

Step-by-step explanation:

likoan [24]3 years ago
7 0

Answer: im pretty sure ur answer is A

Step-by-step explanation:

You might be interested in
Please prove this........​
Crazy boy [7]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π    →     C = π - (A + B)

                                    → sin C = sin(π - (A + B))       cos C = sin(π - (A + B))

                                    → sin C = sin (A + B)              cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

<u>Proof LHS → RHS</u>

LHS:                        (sin 2A + sin 2B) + sin 2C

\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C

\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C

\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C

\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)

\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]

\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B

\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C    \checkmark

7 0
3 years ago
(1,-4) x-2y=8<br> 4x-y=8
deff fn [24]

Answer:

False solution; [1⅐, -3 3⁄7]

Step-by-step explanation:

{x - 2y = 8

{4x - y = 8

-¼[4x - y = 8]

{x - 2y = 8

{-x + ¼y = -2 >> New Equation

____________

-1¾y = 6

y = -3 3⁄7 [Plug this back into both equations to get the x-coordinate of 1⅐]; 1⅐ = x

I am joyous to assist you anytime.

3 0
2 years ago
A environmental initiative has the goal of saving at least 25 2525 million hectares of rainforest through both planting trees an
Anestetic [448]

Answer:

The possible way for the initiative to accomplish its goal without exceeding its budget is use 12.5 hectares for planting trees and 12.5 hectares by purchasing land.

Step-by-step explanation:

Let the variable <em>X</em> represent the amount of land used for planting trees and <em>Y</em> represent the amount of land purchased.

The goal of the environmental initiative is to save at least 25 million hectares of rain forest.

That is:

<em>X</em> + <em>Y</em> = 25....(i)

Now it is provided that:

  • The cost of planting trees is $ 400 per hectare.
  • The cost of purchasing land is $ 260 per hectare.
  • The initiative has a budget of $8,250 million.

Using the above data it can be said that:

400<em>X</em> + 260<em>Y</em> = 8250....(ii)

Solve equations (i) and (ii) simultaneously.

\ \ \ \ x+y=25]\times 260\\400x+260y=8250\\\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\\\\\Rightarrow\\\\260x+260y=6500\\400x+260y=8250\\(-)\_\_\_\_\_\ (-)\_\_\_\_(-)\_\_\_\\\\\Rightarrow\\\\-140x=-1750\\\\x=\frac{1750}{140}\\\\x=12.5

Then the value of <em>y</em> is:

x+y=25\\y=25-x\\y=25-12.5\\y=12.5

Thus, the possible way for the initiative to accomplish its goal without exceeding its budget is use 12.5 hectares for planting trees and 12.5 hectares for purchasing land.

4 0
3 years ago
Given that sine of theta = 21/29, what is the value of cosine of theta, for 0° &lt; theta &lt; 90°?
fenix001 [56]

If the value of θ is 46.4°. Then the value of the cosine of θ will be 20/29.

<h3>What is trigonometry?</h3>

The connection between the lengths and angles of a triangular shape is the subject of trigonometry.

The value of sine of θ is 21/29.

Then the value of θ will be

sin θ = 21/29

     θ = sin⁻¹(21 / 29)

     θ = 46.4°

Then the value of the cosine of θ will be

cos θ = cos 46.4°

cos θ = 20/29

More about the trigonometry link is given below.

brainly.com/question/22698523

#SPJ1

7 0
2 years ago
Assume X and Y are independent random variables with the following distributions:
allsm [11]

Answer:

Step-by-step explanation:

Given that X and Y are independent random variables with the following distributions:

x -1 10 1 2 Total

p 0.3 0.1 0.5 0.1 1

xp -0.3 1 0.5 0.2 1.4

x^2p 0.3 10 0.5 0.4 11.2

Mean of X = 1.4

Var(x) = 11.2-1.4^2 =  9.24    

     

y 2 3 5  

p 0.6 0.3 0.1  1

yp 1.2 0.9 0.5 0 2.6

y^2p 2.4 2.7 2.5 0 7.6

Mean of Y = 2.6

Var(Y) = 11.2-1.4^2 =  0.84

3) W=3+2x

Mean of w =3+2*Mean of x = 7.2

Var (w) = 0+2^2 Var(x)= 36.96

8 0
3 years ago
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