Answer:
Step-by-step explanation:
Given that during the period from 1790 to 1930, the US population P(t) (t in years) grew from 3.9 million to 123.2 million. Throughout this period, P(t) remained close to the solution of the initial value problem.

a) 1930 population is the population at time t = 40 years taking base year as 40
We can solve the differential equation using separation of variables

Resolve into partial fractions

Integrate to get
ln P -0.00474/0.0001489 (ln (0.0001489P-0.03135) = t+C
ln P -31.833 (ln (0.0001489P-0.03135) =t+C

Limiting population would be infinity.
Answer:
e^6 ≈ 403
Step-by-step explanation:
You want the value of e^(4x-2) when x = 2.
<h3>Evaluation</h3>
Put 2 where x is in the expression and do the arithmetic.
e^(4·2 -2) = e^6 ≈ 403.429
The value of the expression is about 403.
70
They both can multiply to reach it and it is the lowest one (no multiple of 7 can end on a 10 below that).
<span># of ways to select 2 red balls: 5C2 = 10
# of random pairs of balls: 12C2 = 66</span>
Answer:
f(x)= 11x +10 +3 or 11x +13
Step-by-step explanation: