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belka [17]
3 years ago
14

Evaluate the expression. 0.3+0.2×0.5

Mathematics
2 answers:
lubasha [3.4K]3 years ago
7 0

Answer:

.4

Step-by-step explanation:

First, multiply .2 by .5 which is .1

add this to .3 and you get .4

Your answer is .4

tangare [24]3 years ago
4 0

Answer:

The answer is 0.4

Step-by-step explanation:

Since we do multiplication first, we do 0.2*0.5. That equals 0.1.

Next, we do addition. 0.3+0.1 is 0.4.

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A cone has A height of 10.3 inches in the diameter of 6 inches what is the volume of the cone
ahrayia [7]

Answer:

V=97.08

Step-by-step explanation:

The formula for the volume of a cone is V= 1/3 pi (r)^2 (h)

To find the radius divide the diameter by 2. 6/2=3

Plugin: V=1/3 pi(3)^2(10.3)=97.08

3 0
3 years ago
Why do we use letters in mathematics?
icang [17]
We use letters to substitute for unknown numbers. I hope this helps. :)
3 0
3 years ago
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6, 3, 4, 7, 3, 7, 8, 5, 7 i. Find the median ii. Find the mean iii. Find the modal mark
4vir4ik [10]

Answer:

i. 6

ii. 5\frac{5}{9}

iii. 7

Step-by-step explanation:

First organize the data from least to greatest.  3,3,4,5,6,7,7,7,8

To find the median, remove the extremes from the data over and over.

3,4,5,6,7,7,7

4,5,6,7,7

5,6,7

6

To find the mean, add all of the numbers and divide by 9

3+3+4+5+6+7+7+7+8=50

50/9=5\frac{5}{9}

To find the modal mark, simply find the number present most in the data set: 7(occurs 3 times)

Hope it helps <3

3 0
3 years ago
Find the inverse function for f(x)=sqrt2x-6 picture below
Olenka [21]

Answer:

y = (x^2 + 6) / 2

Step-by-step explanation:

Original function: \sqrt{2x - 6}

To find the inverse of a function we have to switch the x and y values and solve for y again

x = sqrt (2y-6)

To get rid of a square root we square the square root so:

x^2 = 2y-6

Add 6

x^2 + 6 = 2y

Divide by 2

y = (x^2 + 6) / 2

6 0
3 years ago
Which graph represents y= square root x-4
wolverine [178]

Answer:

Find the domain by finding where the equation is defined. The range is the set of values that correspond with the domain.Domain: [4,∞),{x|x≥4}[4,∞),{x|x≥4}Range: [0,∞),{y|y≥0}

8 0
2 years ago
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