Answer: 1) Both gave same number of candies to each child.
2) Christov gave candy to a greater number of children.
Step-by-step explanation:
Since, Christov initially had 300 pieces of candy, and after he was visited by 17 children, he had 249 pieces left.
Let he gave x candy to each student when he visited 17 children.
Then, 17 x + 249 = 300
⇒ 17 x = 51
⇒ x = 3
Since, he distributes candies in a constant speed.
Therefore, his speed of distribution = 3 candies per child
Now,The function that shows the remaining number of candies Mateus has after distributing candies to n children,
C(n)=270 - 3 n
Initially, n = 0
C(0) = 270
⇒ Mateus has initial number of candies = 270
When he gave candies to one child then remaining candies = 270 - 3 × 1 = 267
Thus, the candies, get by a child from Mateus = 270 - 267 = 3
Since, he distributes candies in a constant speed.
⇒ His speed of distribution = 3 candies per child
1) Therefore, Both Christov and Mateus have same speed of distribution.
2) Since, both have same seed.
⇒ The one who has greater number of candies will be distribute more.
⇒ Christov will give more candies.
