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guapka [62]
3 years ago
15

What are the two constants of proportionality for the relationship between distance in kilometers

Mathematics
1 answer:
andrezito [222]3 years ago
5 0
We call the ratio between two directly proportional quantities the constant of proportionality. When these two quantities may increase or decrease, the constant proportionality always remains the same
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The diameter of Virus A is 2.6 • 10^-7 millimeters. If Virus B has a diameter that is 15 times larger than Virus A, find the dia
Naddik [55]
Multiply (2.6 x 10^-7) by 15 to get

3.9 x 10^-6
3 0
3 years ago
What is the solution for x in the equation?<br> -2x+14+10x=34
NemiM [27]

Answer: The solution of x is 2.5

Step-by-step explanation: hope it helps:)

5 0
2 years ago
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HELP!? ✋
Korolek [52]
All of them are strategies for preventing cancer
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2 years ago
What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2​
tangare [24]

The product is 104 x^{4}+16 \sqrt{30} x^{4}

Explanation:

The given expression is \left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2

Expanding the expression, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)

Now, we shall apply FOIL, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}

Simplifying the terms, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}

Multiplying, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}

Adding the like terms, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}

Thus, the product of the given expression is 104 x^{4}+16 \sqrt{30} x^{4}

7 0
3 years ago
Simplify <br><br> 4 - 8 multiply 3/4 + 1/4
FromTheMoon [43]
The given equation is 4 - 8 * [3/4 + 1/4]
- 4 * [3/4 + 1/4]
- 4 * 1 = - 4
The answer is - 4.
6 0
3 years ago
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