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guapka [62]
3 years ago
15

What are the two constants of proportionality for the relationship between distance in kilometers

Mathematics
1 answer:
andrezito [222]3 years ago
5 0
We call the ratio between two directly proportional quantities the constant of proportionality. When these two quantities may increase or decrease, the constant proportionality always remains the same
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Anyone??? need some help huys:)
atroni [7]

Slope-intercept form:

y = mx + b        "m" is the slope


First i would isolate the "y" in the equation.

2x + y = 4       Subtract 2x on both sides

2x - 2x + y = 4 - 2x

y = 4 - 2x    or     y = -2x + 4

The given line's slope is -2.


For lines to be perpendicular, their slopes have to be the opposite/negative reciprocals (flipped sign and number)

For example:

slope is 2

perpendicular line's slope is -1/2

slope is -2/3

perpendicular line's slope is 3/2


The given line's slope is -2, so the perpendicular line's slope is 1/2.

The 3rd option is your answer

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3 years ago
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saw5 [17]

the answer is $37.60



5 0
3 years ago
MA = 8x – 2, mB = 2x – 8, and mC = 94 – 4x. List the sides of ABC in order from shortest to longest.
LUCKY_DIMON [66]
I hope this helps you

3 0
3 years ago
F(x) = 4x + 2 ; g(x) = 2x ; find f(g(4))<br> HELPP PLS
Dennis_Churaev [7]

Answer:

ion know

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What two numbers add to 9 and multiply to -70
Alborosie
X, y - the numbers

The numbers add to 9 and multiply to -70.
x+y=9 \\&#10;xy=-70 \\ \\&#10;y=9-x \\&#10;xy=-70 \\ \\&#10;\hbox{substitute 9-x for y in the second equation:} \\&#10;x(9-x)=-70 \\&#10;9x-x^2=-70 \\&#10;-x^2+9x+70=0 \\&#10;-x^2+14x-5x+70=0 \\&#10;-x(x-14)-5(x-14)=0 \\&#10;(-x-5)(x-14)=0 \\&#10;-x-5=0 \ \lor \ x-14=0 \\&#10;x=-5 \ \lor \ x=14 \\ \\&#10;y=9-x \\&#10;y=9-(-5) \ \lor \ y=9-14 \\&#10;y=14 \ \lor \ y=-5 \\ \\&#10;(x,y)=(-5,14) \hbox{ or } (x,y)=(14,-5)

The numbers are -5 and 14.
4 0
3 years ago
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