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3 years ago

14

Heather and allison weigh 123 pounds together.If heather weighs 61.25 how much does allison weigh

1 answer:

Rufina [12.5K]3 years ago

7 0

123-61.25=61.75. Allison weighs 61.75 pounds.

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A simple random sample of items resulted in a sample mean of . The population standard deviation is . a. Compute the confidence

Varvara68 [4.7K]

Answer:

(a): The 95% confidence interval is (46.4, 53.6)

(b): The 95% confidence interval is (47.9, 52.1)

(c): Larger sample gives a smaller margin of error.

Step-by-step explanation:

Given

$n = 30$ -- sample size

$\bar x = 50$ -- sample mean

$\sigma = 10$ --- sample standard deviation

Solving (a): The confidence interval of the population mean

Calculate the standard error

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{10}{\sqrt {30}}$

$\sigma_x = \frac{10}{5.478}$

$\sigma_x = 1.825$

The 95% confidence interval for the z value is:

$z = 1.960$

Calculate margin of error (E)

$E = z * \sigma_x$

$E = 1.960 * 1.825$

$E = 3.577$

The confidence bound is:

$Lower = \bar x - E$

$Lower = 50 - 3.577$

$Lower = 46.423$

$Lower = 46.4$ --- approximated

$Upper = \bar x + E$

$Upper = 50 + 3.577$

$Upper = 53.577$

$Upper = 53.6$ --- approximated

<em>So, the 95% confidence interval is (46.4, 53.6)</em>

Solving (b): The confidence interval of the population mean if mean = 90

First, calculate the standard error of the mean

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{10}{\sqrt {90}}$

$\sigma_x = \frac{10}{9.49}$

$\sigma_x = 1.054$

The 95% confidence interval for the z value is:

$z = 1.960$

Calculate margin of error (E)

$E = z * \sigma_x$

$E = 1.960 * 1.054$

$E = 2.06584$

The confidence bound is:

$Lower = \bar x - E$

$Lower = 50 - 2.06584$

$Lower = 47.93416$

$Lower = 47.9$ --- approximated

$Upper = \bar x + E$

$Upper = 50 + 2.06584$

$Upper = 52.06584$

$Upper = 52.1$ --- approximated

<em>So, the 95% confidence interval is (47.9, 52.1)</em>

Solving (c): Effect of larger sample size on margin of error

In (a), we have:

$n = 30$ $E = 3.577$

In (b), we have:

$n = 90$ $E = 2.06584$

<em>Notice that the margin of error decreases when the sample size increases.</em>

4 0

3 years ago

For the following right triangle find the side length x

lbvjy [14]

78’ degrees on the right side

3 0

3 years ago

CAN ANYONE PLEASE EXPLAIN TO ME WHAT ON EARTH THIS MEANS

Shtirlitz [24]

the work that you're required to do has to contain all three requirements in order to earn the maximum number of points, and it also has to be creative (meaning no copying other people's work)

6 0

3 years ago

Pleasaaaaseee answer the all for BRAINLEST answer and thanks

kow [346]

X=2/4=1/2
s=1 1/2
r= 1/2
y= 2/7
w= 1 2/3
p=2/5
Hope this works i can't see the others ok?

3 0

3 years ago

A bag has 3 red marbles, 2 blue, 4 greens and 1 yellow. What is the probability of pulling a blue, putting it back

Tomtit [17]

Answer: 2/25

Step-by-step explanation: Since we are replacing the marbles, these two events are independent which means that the outcome of the first does not affect the outcome of the second.

First find the probability of selecting a blue marble.

There are 2 favorable outcomes, the blue marbles,

and 10 possible outcomes, all the marbles in the bag.

So the probability of selecting a blue marble is 2/10 or 1/5.

<em>Always reduce when finding probability</em>

<em></em>

Now we find the probability of selecting a green marble.

There are 4 green marbles and 10 total so the probability of

selecting a green marble is 4/10 or 2/5.

Now we multiply the probabilities.

So we have 1/5 x 2/5 or 2/25.

3 0

3 years ago