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3 years ago

-4x-y=24 missing value

Mathematics

1 answer:

Lunna [17]3 years ago

7 0

Answer:

For solving x x= -24+y/4 For solving Y y=−24−4x

Step-by-step explanation:

This is solving for x

Add y to both sides.

−4x=24+y

Divide both sides by -4

and the answer is

x= -24+y/4

THis is solving Y

Add 4x to both sides

−y=24+4x

Multiply both sides by -1

and the answer is

y=−24−4x

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Very buys a basket of mangoes that is priced $14 before tax. The sales tax is 6%. What is the total price Avery pays for t

igor_vitrenko [27]

Answer:

Avery needs to pay $14.84

Step-by-step explanation:

When there's a tax we need to sum the original value of the product with the tax's value. To find the amount of money Avery needs to pay in taxes we can apply a rule of three as shown below:

$\frac{14}{x} = \frac{100}{6} \frac{\%}{\%}$

Where "x" is the tax value, and $14 represents 100%, since it's the value used to calculate the tax. We have:

$x = \frac{14*6}{100}\\x = \frac{84}{100}\\x = 0.84$

The value to be paid is the product value plus the tax, therefore:

$\text{paid} = 14 + 0.84 = 14.84$

Avery needs to pay $14.84

6 0

3 years ago

Which equation has the solutions x = -3 ± √3i/2 ?

Maurinko [17]

Answer:Answer is option C : [ $x^{2}$ + 3x + 3 ] =0

Note: None of options matches with given question.

instead of "-3" , there should be "- $\frac{3}{2}$ ".

Step-by-step explanation:

Note: None of options matches with given question.

instead of "-3" , there should be " $\frac{3}{2}$ ".

Here, First thing you have to observe the nature of roots.

∴ x = - $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i and x = - $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$

∴ [ x+( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i) ][ x+( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ]=0

∴ [ $x^{2}$ + x( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i)+ x( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i) + ( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i)( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ]=0

∴ [ $x^{2}$ + $\frac{3}{2}$ x + $\frac{\sqrt{3}}{2}$ ix + $\frac{3}{2}$ x - $\frac{\sqrt{3}}{2}$ ix + (3- $\frac{\sqrt{3}}{2}$ i)(3+ $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + ( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i)( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ - ( $\frac{\sqrt{3}}{2}$ i)( $\frac{\sqrt{3}}{2}$ i) ] =0