4. A stack of playing cards contains 4 jacks, 5 queens, 3 kings, and 3 aces. Two cards will be randomly selected from the stack.
What is the probability that a queen is chosen and replaced, and then a queen is chosen again?
2 answers:
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➷ 5 + 3 + 3 + 4 = 15
5/15 * 5/15 = 25/225
This can be simplified to 1/9
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Total cards = 4 + 5 + 3 + 3 = 15 cards.
There are 5 queens, picking 1 queen would equal 5/15 which reduces to 1/3.
Because the queen is replaced and then you pick again, the probability would be the same as the first time. 1/3.
To find the overall probability of picking 2 queens, multiply each probability together: 1/3 x 1/3 = 1/9 total probability.
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C=10, C=90°, B=30°, A+B+C=180°
A+30°+90°=180°⇒A=60°
cos30°=a/c
cos30°=a/10⇒a=cos30°*10
a<span>≃8.6602
c²=a²+b²⇒b²=c²-a²
b²=10²-8.6602²⇒b²=25
b=5
</span>
Answer:
3x^7 / y
Step-by-step explanation:
√63x^15y^9/√7xy^11
= √ [(63/7) x^(15-1) y^(9-11)
= √9x^14y^-2
= √9x^14 / y^2
= 3x^7 / y
Answer:
the answer is the second choice
Answer:
28cm
Step-by-step explanation:
7x4
or
7+7+7+7
For The first question, the answer is 6.
For the 2nd question, the answer is 127
The solution is on the picture